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The number of grams in a mole of a molecule is found by looking at the Atomic Mass of each element on the Periodic Table. The molar mass of an element is it's atomic mass in grams. The atomic mass of oxygen is 15.999. Since there are two atoms of oxygen in a molecule of oxygen, the molar mass of oxgen (O2) is 15.999 x 2. That comes out to 31.998g/mol, or you can round to 32 if significant figures arn't important to you.

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How many oxygen atoms are present in 40.0 grams of oxygen gas?

There are approximately 0.625 moles of oxygen gas in 40.0 grams. Since the formula for oxygen gas is O2, there are 0.625 moles x 2 = 1.25 moles of oxygen atoms. Therefore, there are approximately 1.25 x 6.022 x 10^23 = 7.53 x 10^23 oxygen atoms in 40.0 grams of oxygen gas.


How many moles of oxygen are represent in 0.16 g of oxygen gas?

To find the number of moles of oxygen in 0.16 g of oxygen gas, you first need to determine the molar mass of oxygen (O2), which is about 32 g/mol. Then, you can use the formula moles = mass / molar mass to calculate the number of moles. In this case, 0.16 g / 32 g/mol = 0.005 moles of oxygen gas.


How many liters of oxygen gas are present in 11.3 grams of oxygen gas?

To find the number of liters of oxygen gas in 11.3 grams, you need to convert the grams to moles using the molar mass of oxygen (16 g/mol). Then, you can use the ideal gas law to find the volume of gas at standard temperature and pressure (STP), which is 1 mole of gas occupying 22.4 liters at 0 degrees Celsius and 1 atm pressure.


How many moles of oxygen in 30L of oxygen gas?

To determine the number of moles of oxygen in 30L of oxygen gas, you would first need to convert 30L to volume at standard temperature and pressure (STP), which is 22.4L/mol. Next, you can use the ideal gas law (PV = nRT) to calculate the number of moles of oxygen gas present in the given volume.


How many moles of oxygen gas are needed to react with 10.0 mol of ammonia?

The balanced chemical equation for the reaction between ammonia (NH3) and oxygen gas (O2) is 4 NH3 + 5 O2 → 4 NO + 6 H2O. This means that 5 moles of O2 are needed to react with 4 moles of NH3. With 10.0 moles of NH3, you would need 12.5 moles of O2 (10.0 moles NH3 x 5 moles O2 / 4 moles NH3).

Related Questions

How many grams of O2 are in 50moles of the oxygen gas?

Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : mass = Mr x number of moles mass = 32g/mol x 50mols = 1600g


How many moles are in 5.56g of oxygen gas (O2)?

The answer is 0,173 moles.


How many grams are in 6.5 moles of oxygen gas?

6,5 moles oxygen equals 208 g.


How many moles of oxygen gas are there in 135 liters of oxygen at Standard Temerature Pressure?

The equivalent in moles is 6,03.


How many moles of oxygen gas O2 are in 64 grams of O2?

The answer is 2 moles.


How many oxygen atoms are present in 40.0 grams of oxygen gas?

There are approximately 0.625 moles of oxygen gas in 40.0 grams. Since the formula for oxygen gas is O2, there are 0.625 moles x 2 = 1.25 moles of oxygen atoms. Therefore, there are approximately 1.25 x 6.022 x 10^23 = 7.53 x 10^23 oxygen atoms in 40.0 grams of oxygen gas.


What is the mass of 0.2 moles of oxygen gas?

The mass of 0,2 moles of oxygen gas is 6,4 g.


How many moles of potassium chlorate produce 6 moles of oxygen gas?

For every mole of potassium chlorate (KClO3) that decomposes, three moles of oxygen gas (O2) are produced. Therefore, to produce 6 moles of oxygen gas, 2 moles of potassium chlorate are needed.


How many moles of oxygen are represent in 0.16 g of oxygen gas?

To find the number of moles of oxygen in 0.16 g of oxygen gas, you first need to determine the molar mass of oxygen (O2), which is about 32 g/mol. Then, you can use the formula moles = mass / molar mass to calculate the number of moles. In this case, 0.16 g / 32 g/mol = 0.005 moles of oxygen gas.


How many moles of carbon dioxide are produced when 10.0 moles of propane are burned in excess oxygen on gas grill?

30 moles


How many no of moles are there in 16 gm of oxygen gas?

To find the number of moles in 16 g of oxygen gas, you need to divide the given mass by the molar mass of oxygen. The molar mass of oxygen (O2) is 32 g/mol. Therefore, 16 g / 32 g/mol = 0.5 moles of oxygen gas.


How many moles potassium chlorate must be used to produce 6 moles of oxygen gas?

We need 3 moles of potassium perchlorate.