The number of grams in a mole of a molecule is found by looking at the Atomic Mass of each element on the Periodic Table. The molar mass of an element is it's atomic mass in grams. The atomic mass of oxygen is 15.999. Since there are two atoms of oxygen in a molecule of oxygen, the molar mass of oxgen (O2) is 15.999 x 2. That comes out to 31.998g/mol, or you can round to 32 if significant figures arn't important to you.
There are approximately 0.625 moles of oxygen gas in 40.0 grams. Since the formula for oxygen gas is O2, there are 0.625 moles x 2 = 1.25 moles of oxygen atoms. Therefore, there are approximately 1.25 x 6.022 x 10^23 = 7.53 x 10^23 oxygen atoms in 40.0 grams of oxygen gas.
To find the number of moles of oxygen in 0.16 g of oxygen gas, you first need to determine the molar mass of oxygen (O2), which is about 32 g/mol. Then, you can use the formula moles = mass / molar mass to calculate the number of moles. In this case, 0.16 g / 32 g/mol = 0.005 moles of oxygen gas.
To find the number of liters of oxygen gas in 11.3 grams, you need to convert the grams to moles using the molar mass of oxygen (16 g/mol). Then, you can use the ideal gas law to find the volume of gas at standard temperature and pressure (STP), which is 1 mole of gas occupying 22.4 liters at 0 degrees Celsius and 1 atm pressure.
To determine the number of moles of oxygen in 30L of oxygen gas, you would first need to convert 30L to volume at standard temperature and pressure (STP), which is 22.4L/mol. Next, you can use the ideal gas law (PV = nRT) to calculate the number of moles of oxygen gas present in the given volume.
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen gas (O2) is 4 NH3 + 5 O2 → 4 NO + 6 H2O. This means that 5 moles of O2 are needed to react with 4 moles of NH3. With 10.0 moles of NH3, you would need 12.5 moles of O2 (10.0 moles NH3 x 5 moles O2 / 4 moles NH3).
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : mass = Mr x number of moles mass = 32g/mol x 50mols = 1600g
The answer is 0,173 moles.
6,5 moles oxygen equals 208 g.
The equivalent in moles is 6,03.
The answer is 2 moles.
There are approximately 0.625 moles of oxygen gas in 40.0 grams. Since the formula for oxygen gas is O2, there are 0.625 moles x 2 = 1.25 moles of oxygen atoms. Therefore, there are approximately 1.25 x 6.022 x 10^23 = 7.53 x 10^23 oxygen atoms in 40.0 grams of oxygen gas.
The mass of 0,2 moles of oxygen gas is 6,4 g.
For every mole of potassium chlorate (KClO3) that decomposes, three moles of oxygen gas (O2) are produced. Therefore, to produce 6 moles of oxygen gas, 2 moles of potassium chlorate are needed.
To find the number of moles of oxygen in 0.16 g of oxygen gas, you first need to determine the molar mass of oxygen (O2), which is about 32 g/mol. Then, you can use the formula moles = mass / molar mass to calculate the number of moles. In this case, 0.16 g / 32 g/mol = 0.005 moles of oxygen gas.
30 moles
To find the number of moles in 16 g of oxygen gas, you need to divide the given mass by the molar mass of oxygen. The molar mass of oxygen (O2) is 32 g/mol. Therefore, 16 g / 32 g/mol = 0.5 moles of oxygen gas.
We need 3 moles of potassium perchlorate.