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For this you need the atomic (molecular) mass of NO. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. NO=30.0 grams
6.64 grams NO / (30.0 grams)= .221 moles NO
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How many grams of nitrogen dioxide must react with water to produce 5.00 x 1022 molecules of nitrogen monoxide?
To find the grams of nitrogen dioxide needed, first calculate the moles of nitrogen monoxide using Avogadro's number. Then, use the balanced chemical equation to determine the moles of nitrogen dioxide required. Finally, convert moles to grams using the molar mass of nitrogen dioxide.
When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form how many grams of water form?
To calculate the grams of water formed, we first need to determine the moles of nitrogen and oxygen produced. Using the given data, we find that 14 grams of nitrogen is equivalent to 1 mole and 8 grams of oxygen is also equivalent to 0.5 moles. In the explosion, these moles of nitrogen and oxygen will combine with hydrogen to form water. Since the molar ratio of hydrogen to nitrogen and oxygen is 2:1, the moles of water produced will be 1 mole (from nitrogen) + 0.5 moles (from oxygen) = 1.5 moles. Finally, converting moles to grams, 1.5 moles of water is equal to 18 grams. Thus, 18 grams of water would form during the explosion.
How many moles of nitrogen gas are there in 35.7 gm of nitrogen gas?
To calculate the number of moles of nitrogen gas in 35.7 g, you can use the molar mass of nitrogen, which is 28 g/mol. First, divide the given mass by the molar mass to find the number of moles: ( \frac{35.7 , \text{g}}{28 , \text{g/mol}} \approx 1.275 , \text{mol}). Therefore, there are approximately 1.275 moles of nitrogen gas in 35.7 g.
How many molecules of carbon monoxide are present in 3.69 grams of this compound?
To find the number of molecules of carbon monoxide in 3.69 grams, first calculate the number of moles using the molar mass of carbon monoxide (28.01 g/mol). Next, use Avogadro's number to determine the number of molecules in those moles of carbon monoxide.
How many moles are in 21.4 mg of nitrogen dioxide?
To find the number of moles, you need to first convert 21.4 mg of nitrogen dioxide to grams by dividing by 1000 (since 1 gram = 1000 mg). Then, calculate the moles using the molar mass of nitrogen dioxide (NO2), which is 46.01 g/mol. 21.4 mg is equal to 0.0214 grams. Dividing 0.0214 g by the molar mass of NO2 gives you approximately 0.00047 moles of nitrogen dioxide.
How many grams of nitrogen dioxide must react with water to produce 5.00 x 1022 molecules of nitrogen monoxide?
To find the grams of nitrogen dioxide needed, first calculate the moles of nitrogen monoxide using Avogadro's number. Then, use the balanced chemical equation to determine the moles of nitrogen dioxide required. Finally, convert moles to grams using the molar mass of nitrogen dioxide.
How many grams in 5.0x1022 molecules of nitrogen monoxide?
To find the number of grams in 5.0x10^22 molecules of nitrogen monoxide (NO), you need to convert the number of molecules to moles and then from moles to grams. First, calculate the number of moles by dividing the number of molecules by Avogadro's number (6.022x10^23 molecules/mol). Then, use the molar mass of NO (30.01 g/mol) to convert moles to grams.
How many moles of nitrogen are in 15 grams of nitrogen?
15 grams of nitrogen are equal to 1,071 moles.
How many moles of nitrogen are there in 29 grams of nitrogen?
There are 29/14, or just over 2 moles of nitrogen in 19 grams.
How many moles are in 56 grams of carbon monoxide?
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
How many moles of NO2 can be produced given 1.35 moles of nitrogen monoxide?
The reaction to form nitrogen dioxide using nitric oxide is; 2NO(g) + O2(g) -> 2NO2(g) As the stoichiometry between the substances are 1:1, 1.35 moles of nitrogen monoxide is needed.
How many grams of nitrogen are present in 1.78 moles of nitrogen trifluoride?
The answer is 24,92 g nitrogen.
How many moles of molecules are in 550 grams of nitrogen dioxide?
550 g of nitrogen dioxide is equal to 11,94 moles.
How many moles of nitrogen in 42 grams of nitrogen?
To find the number of moles of nitrogen in 42 grams, you first need to divide the given mass by the molar mass of nitrogen, which is approximately 14 grams per mole. Therefore, 42 grams of nitrogen would be equal to 3 moles of nitrogen.
How many grams of carbon monoxide (CO) are there in 2.55 moles of the ompound?
To determine the mass of carbon monoxide in 2.55 moles, we first find the molar mass of CO, which is 28.01 g/mol. Then, we multiply the molar mass by the number of moles: 28.01 g/mol * 2.55 mol = 71.53 grams of CO in 2.55 moles of the compound.
When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form how many grams of water form?
To calculate the grams of water formed, we first need to determine the moles of nitrogen and oxygen produced. Using the given data, we find that 14 grams of nitrogen is equivalent to 1 mole and 8 grams of oxygen is also equivalent to 0.5 moles. In the explosion, these moles of nitrogen and oxygen will combine with hydrogen to form water. Since the molar ratio of hydrogen to nitrogen and oxygen is 2:1, the moles of water produced will be 1 mole (from nitrogen) + 0.5 moles (from oxygen) = 1.5 moles. Finally, converting moles to grams, 1.5 moles of water is equal to 18 grams. Thus, 18 grams of water would form during the explosion.
How many moles of nitrogen are contained in a 35.0g sample?
To find the number of moles of nitrogen in a 35.0g sample, you need to divide the mass of the sample by the molar mass of nitrogen. The molar mass of nitrogen is approximately 14.01 g/mol. Therefore, 35.0g / 14.01 g/mol = approximately 2.5 moles of nitrogen.
