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To find the number of moles in 4.75g of sodium hydroxide, you first need to determine the molar mass of sodium hydroxide (NaOH), which is about 40g/mol. Then divide the given mass (4.75g) by the molar mass to obtain the number of moles: 4.75g / 40g/mol = 0.119 moles of NaOH.
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How many moles of sodium hydroxide will react with 17 moles of sulfuric acid?
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
How many grams of sodium hydroxide are there in 0.150 mol?
To find the grams of sodium hydroxide in 0.150 mol, first calculate the molar mass of sodium hydroxide, which is approximately 40 g/mol. Then, multiply the molar mass by the number of moles: 40 g/mol x 0.150 mol = 6 grams of sodium hydroxide.
How many moles of sodium hydroxide are in 40 grams of sodium hydroxide?
To find the number of moles in 40 grams of sodium hydroxide, you first need to calculate the molar mass of NaOH. The molar mass of NaOH is about 40 g/mol. Then, you divide the given mass by the molar mass to get the number of moles. So, 40 grams divided by 40 g/mol is equal to 1 mole of NaOH.
How many grams of sodium hydroxide are present in 675 mL of a 0.500M solution?
To calculate the grams of sodium hydroxide present in the solution, first calculate the number of moles using the formula: moles = Molarity (M) x Volume (L). Then, use the molar mass of sodium hydroxide (NaOH) to convert moles to grams. The molar mass of NaOH is 40 g/mol. Thus, in this case, you have 0.3375 moles of NaOH and if you convert this to grams, it would be 13.5 grams.
HOW many moles are in 4.5 moles of sodium fluoride?
There are 4.5 moles of sodium fluoride in 4.5 moles of sodium fluoride.
How many moles of sodium hydroxide will react with 17 moles of sulfuric acid?
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
How many moles of sodium sulphate can be formed from two moles of sodium hydroxide?
No amount of sodium sulphate can be formed from sodium hydroxide alone, because sodium sulfate contains sulfur and sodium hydroxide does not. By neutralization with sulphuric acid, one formula unit of sodium sulphate can be formed from two moles of sodium hydroxide, according to the equation 2 NaOH + H2SO4 -> Na2SO4 + 2 H2O.
How many moles are in 8 grams of sodium hydroxide?
0.2 mol
If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
You would have 1.5 moles of sodium hydroxide. This is calculated by dividing the mass of sodium hydroxide by its molar mass: 60 grams / 40 grams/mole = 1.5 moles.
How many moles of sodium hydroxide will be produced from the complete reaction of 15.0 g sodium?
Sodium reacts with water. 0.652 NaOH moles will form.
How many moles in 20g of sodium hydroxide?
To determine the number of moles in 20g of sodium hydroxide, you need to divide the given mass by the molar mass of sodium hydroxide. The molar mass of NaOH is 40 g/mol (sodium: 23 g/mol, oxygen: 16 g/mol, hydrogen: 1 g/mol). So, 20g NaOH / 40 g/mol = 0.5 moles of sodium hydroxide.
How many millimoles are in 12g of sodium hydroxide?
The molecular weight of sodium hydroxide is 40g/mol. To get the amount of moles, you have to divide the weight by molecular mass. 12g / 40 is 0.3 moles. This is 300 millimoles.
How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
The balanced chemical equation for the neutralization between sodium hydroxide (NaOH) and nitric acid (HNO3) is 1 mol of NaOH reacts with 1 mol of HNO3. Therefore, 20 moles of nitric acid would require 20 moles of sodium hydroxide to neutralize it.
How many grams of sodium hydroxide are there in 0.150 mol?
To find the grams of sodium hydroxide in 0.150 mol, first calculate the molar mass of sodium hydroxide, which is approximately 40 g/mol. Then, multiply the molar mass by the number of moles: 40 g/mol x 0.150 mol = 6 grams of sodium hydroxide.
How many moles of sodium hydroxide are formed when 46 g of sodium react with water?
When sodium reacts with water, it forms sodium hydroxide. The molar mass of sodium is 23 g/mol. By dividing the given mass (46 g) by the molar mass of sodium (23 g/mol), we find that 2 moles of sodium are involved in the reaction, producing 2 moles of sodium hydroxide.
How many moles of sodium hydroxide are in 40 grams of sodium hydroxide?
To find the number of moles in 40 grams of sodium hydroxide, you first need to calculate the molar mass of NaOH. The molar mass of NaOH is about 40 g/mol. Then, you divide the given mass by the molar mass to get the number of moles. So, 40 grams divided by 40 g/mol is equal to 1 mole of NaOH.
How many moles are there in 8 g sodium hydroxide?
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
