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To determine the number of molecules in 120 grams of bromine gas, you first need to calculate the moles of bromine using its molar mass (molar mass of Br2 = 159.808 g/mol). Then, use Avogadro's number (6.022 x 10^23) to find the number of molecules in that many moles of bromine gas.
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How many grams in 10 ml of bromine?
The density of bromine is 3.12 g/ml, therefore 10 ml of bromine would weigh 31.2 grams.
How many grams are in one mole of Bromine trifluoride?
The molar mass of Bromine trifluoride is approximately 126.893 g/mol. Therefore, one mole of Bromine trifluoride contains 126.893 grams.
How many moles of bromine gas are in 37.7 grams?
To determine the number of moles of bromine gas in 37.7 grams, you need to divide the given mass by the molar mass of bromine. The molar mass of bromine is approximately 79.904 g/mol. So, 37.7 grams of bromine is equal to 0.471 moles (37.7 g ÷ 79.904 g/mol).
How many moles of bromine are in 2.60100 grams of bromine?
To determine the number of moles in 2.60100 grams of bromine, we first need to calculate the molar mass of bromine, which is 79.904 g/mol. Then, we use the formula: moles = mass / molar mass. Substituting the values, we get moles = 2.60100 g / 79.904 g/mol = 0.03255 moles of bromine.
How many moles are in 0.476 grams of bromine?
To find the number of moles in 0.476 grams of bromine, you first need to determine the molar mass of bromine, which is approximately 79.904 g/mol. Then, you can use the formula: moles = mass (g) / molar mass (g/mol). Therefore, in this case, 0.476 grams of bromine is equivalent to 0.006 moles.
How many Number of atoms are present in bromine?
Bromine exists as diatomic molecules, meaning each molecule consists of two bromine atoms bonded together. Therefore, in one molecule of bromine, there are two bromine atoms.
How many molecules are in 46.7 grams of bromine?
Elemental Bromine exists as a diatomic molecule, its atomic number is 35 and its atomic weight is 79.904. A molecule would therefore have a weight of 159.808.A Mole is defined as the amount of any substance that contains as many elementary entities (in this case diatomic molecules) as Avogadro's constant ( 602,214,150,000,000,000,000,000).A mole of Bromine would therefore weigh 159.808 grams.Therefore 46.7 grams of Bromine would contain(46.7)/159.808)*602,214,150,000,000,000,000,000Which is 0.292225670804966 * 602,214,150,000,000,000,000,000Which = 175,982,433,951,992,400,000,000 molecules.
How many moles of bromine atoms are in 2.60x102 grams of bromine?
2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
How many grams in 10 ml of bromine?
The density of bromine is 3.12 g/ml, therefore 10 ml of bromine would weigh 31.2 grams.
How many atoms and molecules are present in 64 grams of sulphur?
12.044*10^23 atoms 1.5055*10^23 S8 molecules
How many grams are in one mole of Bromine trifluoride?
The molar mass of Bromine trifluoride is approximately 126.893 g/mol. Therefore, one mole of Bromine trifluoride contains 126.893 grams.
How many moles of bromine gas are in 37.7 grams?
To determine the number of moles of bromine gas in 37.7 grams, you need to divide the given mass by the molar mass of bromine. The molar mass of bromine is approximately 79.904 g/mol. So, 37.7 grams of bromine is equal to 0.471 moles (37.7 g ÷ 79.904 g/mol).
How many molecules are present in 691 grams of potassium carbonate?
30.115*10^23 molecules
How many grams are in 10 ml of Bromine?
The density of liquid bromine is around 3.12 grams per milliliter, so 10 mL of bromine would weigh approximately 31.2 grams.
How many molecules would be in two moles of bromine gas (Br)?
The number of molecules is approx. 12.10.e+23.
How many molecule in 25 grams of NH3?
25 grams / (17 grams/mole) x 6.022x1023 molecules/mole = 8.9x1023 molecules
How many moles of bromine are in 2.60100 grams of bromine?
To determine the number of moles in 2.60100 grams of bromine, we first need to calculate the molar mass of bromine, which is 79.904 g/mol. Then, we use the formula: moles = mass / molar mass. Substituting the values, we get moles = 2.60100 g / 79.904 g/mol = 0.03255 moles of bromine.
