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6.02 x 1023

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To find the number of molecules of LiCl in a 127.17 g sample, you first need to convert the mass of LiCl to moles using its molar mass. Then, use Avogadro's number (6.022 x 10^23) to convert moles to molecules. Calculate the number of molecules of LiCl in the sample using these values.

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Q: How many molecules of LiCl are in a 127.17 g sample?
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A student weighed 0.550 grams of lithium chloride LiCl to use in a reaction How many moles is this?

To find the number of moles in 0.550 grams of LiCl, divide the mass by the molar mass of LiCl, which is approximately 42.4 g/mol. 0.550 g LiCl / 42.4 g/mol LiCl ≈ 0.013 mol LiCl. Therefore, the student has approximately 0.013 moles of LiCl.


How many types of molecules with different masses exist in a sample of chlorine gas if the same exists entirely as diatomic molecules?

In a sample of chlorine gas, all molecules are diatomic composed of two chlorine atoms. This means there is only one type of molecule in the sample, with a molecular formula Cl2.


How many formula units are there in 98.2g of LiCl?

To find the number of formula units in 98.2g of LiCl, first calculate the molar mass of LiCl (6.94 + 35.45 = 42.39g/mol). Then divide the given mass by the molar mass to get the number of moles (98.2g / 42.39g/mol = 2.31 mol). Lastly, use Avogadro's number (6.022 x 10^23 formula units/mol) to determine that there are approximately 1.39 x 10^24 formula units in 98.2g of LiCl.


How many loaned pairs of electrons does LiCl have?

LiCl does not have any loaned pairs of electrons. In LiCl, lithium donates one electron to chlorine to form an ionic bond, leading to a full outer shell for both elements.


How are atoms related to molecules in a sample of a compound?

Atoms are the building blocks of molecules. Molecules are formed when two or more atoms chemically combine through bonds. A sample of a compound is made up of these molecules, which in turn are made up of individual atoms.

Related questions

How many molecules of LiCl are in a 127.17g sample?

To calculate the number of molecules of LiCl in a 127.17g sample, you first need to determine the number of moles of LiCl in the sample using the molar mass of LiCl (6.94g/mol for Li and 35.45g/mol for Cl). Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to molecules.


How many molecules are in LiCi are in a 127.17 g sample?

To determine the number of molecules in a sample of LiCl, we need to first calculate the number of moles using the molar mass of LiCl (42.39 g/mol). Next, we use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, there are approximately (127.17 \text{ g} / 42.39 \text{ g/mol} \approx 3 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} ≈ 1.8 \times 10^{24}) molecules of LiCl in 127.17 g.


How many formula units of LiCl are in 127.17 g sample?

127.17 g LiCl x 1 mol/42.4 g x 6.02x10^23 Form.Units/moles = 1.81x10^24 Formula Units.


How many formula units of LiCl are in a 127.17 g sample?

127.17 g LiCl x 1 mol/42.4 g x 6.02x10^23 Form.Units/moles = 1.81x10^24 Formula Units.


How many molecules are there in 9.34 grams of water?

Assuming the question refers to LiCl (Lithium chloride) which has a molecular weight 42.39. Avogadro's constant states there are 6.022 141 79x1023 molecules per mole 9.34 g LiCl is 9.34/42.39 mole (0.220 mole) LiCl The number of molecules is therefore 6.022 141 79x1023x 0.220 =1.326x1023 molecules


How many molecules are in sample 57.45 CF2Cl2?

To calculate the number of molecules in a sample, you need to know the mass of the sample and the molar mass of the compound. Then you can use Avogadro's number (6.022 x 10^23) to convert from grams to molecules.


A student weighed 0.550 grams of lithium chloride LiCl to use in a reaction How many moles is this?

To find the number of moles in 0.550 grams of LiCl, divide the mass by the molar mass of LiCl, which is approximately 42.4 g/mol. 0.550 g LiCl / 42.4 g/mol LiCl ≈ 0.013 mol LiCl. Therefore, the student has approximately 0.013 moles of LiCl.


How many molecules are contained in a 5.20 g sample of dimethylmercury?

The answer is 1,357.10 ex.23 molecules.


How many molecules are contained in a 4.15-g sample of dimethylmercury?

To calculate the number of molecules in a sample of dimethylmercury, you would first need to determine the number of moles in the sample using the molar mass of dimethylmercury. Then you can use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules.


How many molecules are contained in a g sample of dimethylmercury?

1.24*10^22


How many moles of molecules does a 36g sample of carbon briquets contain?

3


How many molecules are contained in a 6.95 g sample of dimethylmercury?

1.814*1022