0
Three ions of bromide will combine with one ion of aluminum to form aluminum bromide (AlBr3). This is because aluminum has a +3 charge and bromide ions each have a -1 charge, so three bromide ions are needed to balance the +3 charge of aluminum.
Add your answer:
Earn +20 pts
How many bromide ions can combine with one ion of barium to form an ionic compound?
Each ion of barium can combine with two bromide ions to form an ionic compound due to the 2+ charge of the barium ion and the 1- charge of the bromide ion, resulting in a neutral compound.
How many moles of bromide ions are present in 750.0 mL of 1.35 M MgBr2?
There are 1.35 moles of MgBr2 in 1 L of solution, which corresponds to 2 moles of bromide ions. Therefore, in 750.0 mL of 1.35 M MgBr2 solution, there will be 1.0125 moles of bromide ions.
How many chloride ions are there in 3 mol of aluminum chloride?
There are 6 moles of chloride ions in 3 mol of aluminum chloride, as there are two chloride ions for every one aluminum ion in the formula AlCl3.
How many moles of chloride ions are in 0.2520g of aluminum chloride?
To find the number of moles of chloride ions in aluminum chloride, you first need to convert 0.2520g of aluminum chloride to moles. Then, since there are three chloride ions per one aluminum chloride molecule, you would multiply the number of moles of aluminum chloride by 3 to find the moles of chloride ions.
How many mol of bromide ions are in 0.500 L of a 0.300 M solution of AlBr3?
Since AlBr3 dissociates into three bromide ions per formula unit, the concentration of bromide ions in the solution would be 3 times the concentration of AlBr3. To calculate the number of moles of bromide ions, multiply the concentration of AlBr3 by 3 and then by the volume of the solution. Therefore, there would be 0.450 moles of bromide ions in 0.500 L of a 0.300 M solution of AlBr3.
How many bromide ions can combine with one ion of barium to form an ionic compound?
Each ion of barium can combine with two bromide ions to form an ionic compound due to the 2+ charge of the barium ion and the 1- charge of the bromide ion, resulting in a neutral compound.
How many Li ions are needed to combine with one bromide ion?
One lithium ion is needed to combine with one bromide ion to form lithium bromide (LiBr).
How many moles of bromide are there in Iron Bromide?
To determine how many moles of bromide are in iron (III) bromide (FeBr3), you can use the chemical formula FeBr3 to see that there are three moles of bromide ions for every mole of iron (III) bromide. So, the number of moles of bromide ions is equal to the number of moles of FeBr3.
How many moles of bromide ions are present in 750.0 mL of 1.35 M MgBr2?
There are 1.35 moles of MgBr2 in 1 L of solution, which corresponds to 2 moles of bromide ions. Therefore, in 750.0 mL of 1.35 M MgBr2 solution, there will be 1.0125 moles of bromide ions.
How many fluoride ions are in 1.46 moles of aluminum fluoride?
There would be 4.38 moles of fluoride ions in 1.46 moles of aluminum fluoride, as the formula for aluminum fluoride is AlF3 with three fluoride ions per molecule of aluminum fluoride.
How many chloride ions are required to neutralize one aluminum ion?
Three chloride ions are required to neutralize one aluminum ion. Aluminum has a 3+ charge, while chloride ions have a 1- charge, so three chloride ions are needed to balance the charge.
How many atoms are in aluminum bromine?
One molecule of aluminum bromide contains one aluminum atom and three bromine atoms, totaling four atoms.
How many ions are in sulfate in Al2SO4?
There are 3 ions in the formula Al2SO4 (2 aluminum and 1 sulfate), but this formula is wrong. The formula of aluminum sulfate is Al2(SO4)3 which contains 5 ions: 2 aluminum ions and 3 sulfate ions.
How many ions does MgBr2 have?
One formula unit of MgBr2 has three ions; one Mg2+ ion and two Br- ions. One mole of MgBr2 formula units has one mole of Mg2+ ions and two moles of Br- ions, for a total of three moles of ions.
How many chlorine ions are required to bond with one aluminuim ion?
Three chlorine ions are required to bond with one aluminum ion in order to form the compound aluminum chloride. This results in a stable compound with a 1:3 ratio of aluminum to chlorine ions.
How many chlorine ions are required to bond with aluminum ion?
Three chlorine ions are required to bond with one aluminum ion to form the compound aluminum chloride. This is because aluminum has a 3+ charge and chlorine has a 1- charge, so the formula for aluminum chloride is AlCl3.
How many chloride ions combine with a single sodium ion?
It is a lattice. There are 6 cl- ions around a sodium ion.
