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7.5 grams of CaCl2 is how many moles?
To find the number of moles of CaCl2, you need to use its molar mass. The molar mass of CaCl2 is approximately 110.98 g/mol. Dividing 7.5 g by the molar mass gives you approximately 0.067 moles of CaCl2.
How many moles of CaCl2 contain 1.261024 formula units of CaCl2?
To calculate the number of moles of CaCl2, you first need to find the molar mass of CaCl2, which is 110.98 g/mol. Then, you divide the given number of formula units (1.261024) by Avogadro's number to convert it to moles. So, the answer would be approximately 1.14 moles of CaCl2.
How many grams of CaCl2 are needed to prepare 2.00 l if 0.700 M CaCl2 solution?
To prepare a 0.700 M solution of CaCl2 in 2.00 L of solution, you would need 2.00 L * 0.700 mol/L = 1.40 moles of CaCl2. With the molar mass of CaCl2 being 110.98 g/mol, you would need 1.40 moles * 110.98 g/mol ≈ 155.37 grams of CaCl2.
How many moles are present in 18.4g of CaCl2?
To determine the number of moles in 18.4g of CaCl2, first calculate the molar mass of CaCl2 (40.08 + 2*35.45 = 110.98 g/mol). Then, divide the given mass by the molar mass to find the number of moles. In this case, 18.4g / 110.98 g/mol = 0.165 moles of CaCl2.
How many moles of CaCl2 contain 1.26x1024 formula units of CaCl2?
To calculate the number of moles, first find the molar mass of CaCl2 (40.08 g/mol for Ca + 2 * 35.45 g/mol for Cl). Then divide the given number of formula units by Avogadro's number (6.022 x 10^23 formula units/mol) to get the number of moles.
