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377.332g (anhydrous)

438.5966g (monohydrate)

499.8476g (dihydrate)

622.353g (tetrahydrate)

744.872g (hexahydrate)

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14y ago
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5mo ago

The molar mass of CaCl2 is 110.98 g/mol. To find the mass of 3.40 moles of CaCl2, you would multiply the number of moles by the molar mass: 3.40 moles x 110.98 g/mol = 377.192 g. Therefore, 3.40 moles of CaCl2 is equal to 377.192 grams of CaCl2.

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Q: How many grams of CaCl2 equal 3.40 moles of CaCl2?
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7.5 grams of CaCl2 is how many moles?

To find the number of moles of CaCl2, you need to use its molar mass. The molar mass of CaCl2 is approximately 110.98 g/mol. Dividing 7.5 g by the molar mass gives you approximately 0.067 moles of CaCl2.


How many moles of CaCl2 contain 1.261024 formula units of CaCl2?

To calculate the number of moles of CaCl2, you first need to find the molar mass of CaCl2, which is 110.98 g/mol. Then, you divide the given number of formula units (1.261024) by Avogadro's number to convert it to moles. So, the answer would be approximately 1.14 moles of CaCl2.


How many grams of CaCl2 are needed to prepare 2.00 l if 0.700 M CaCl2 solution?

To prepare a 0.700 M solution of CaCl2 in 2.00 L of solution, you would need 2.00 L * 0.700 mol/L = 1.40 moles of CaCl2. With the molar mass of CaCl2 being 110.98 g/mol, you would need 1.40 moles * 110.98 g/mol ≈ 155.37 grams of CaCl2.


How many moles are present in 18.4g of CaCl2?

To determine the number of moles in 18.4g of CaCl2, first calculate the molar mass of CaCl2 (40.08 + 2*35.45 = 110.98 g/mol). Then, divide the given mass by the molar mass to find the number of moles. In this case, 18.4g / 110.98 g/mol = 0.165 moles of CaCl2.


How many moles of CaCl2 contain 1.26x1024 formula units of CaCl2?

To calculate the number of moles, first find the molar mass of CaCl2 (40.08 g/mol for Ca + 2 * 35.45 g/mol for Cl). Then divide the given number of formula units by Avogadro's number (6.022 x 10^23 formula units/mol) to get the number of moles.

Related questions

7.5 grams of CaCl2 is how many moles?

To find the number of moles of CaCl2, you need to use its molar mass. The molar mass of CaCl2 is approximately 110.98 g/mol. Dividing 7.5 g by the molar mass gives you approximately 0.067 moles of CaCl2.


How many grams of Cl are in 435 g of CaCl2?

There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.


How many grams are in 0.74 moles of CaCl2?

To find the number of grams in 0.74 moles of CaCl2, you would first need to determine the molar mass of CaCl2. The molar mass of CaCl2 is 110.98 g/mol. Then, you would multiply the number of moles (0.74) by the molar mass (110.98 g/mol) to obtain the mass in grams. Therefore, 0.74 moles of CaCl2 is equivalent to 82.21 grams.


How many grams of CaCl2 can be obtained if 14.6 g HCl is allowed to react with excess CaCO3?

The balanced chemical equation for the reaction between HCl and CaCO3 is: 2HCl + CaCO3 → CaCl2 + H2O + CO2. The molar ratio between HCl and CaCl2 is 2:1. Calculate the number of moles of HCl from 14.6 g, then use the mole ratio to find the moles of CaCl2. Finally, convert moles of CaCl2 to grams.


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