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There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.

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14y ago
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5mo ago

In NaCl, the ratio of sodium to chloride atoms is 1:1. Therefore, in 2.35 mol of NaCl, there are 2.35 mol of sodium atoms. To find the number of sodium atoms, you would multiply the number of moles by Avogadro's number (6.022 x 10^23).

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Q: How many atoms of sodium are in 2.35 mol of NaCl?
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