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For this problem, the Atomic Mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.

10.6 grams Mg / (24.3 grams) × (6.02 × 1023 atoms) = 2.63 × 1023 atoms

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15y ago
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6mo ago

The molar mass of magnesium is approximately 24.3 g/mol. Therefore, 36 g of magnesium is equal to 1.48 moles. Since 1 mole of magnesium contains 6.022 x 10^23 atoms, 1.48 moles would contain approximately 8.9 x 10^23 atoms.

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12y ago

The gram atomic mass of magnesium is 24.305. Therefore, 36 g of magnesium contains (36/24.305) X Avogadro's Number or 8.9 X 1023 atoms, to the justified number of significant digits.

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12y ago

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Q: How many atoms in 36g of magnesium?
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