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To determine the number of atoms in 16g of oxygen gas, you first need to calculate the number of moles of oxygen using the molar mass of oxygen. Oxygen has a molar mass of 16g/mol. So, 16g of oxygen gas is equal to 1 mole of oxygen gas. One mole of oxygen gas contains approximately 6.022 x 10^23 atoms (Avogadro's number). Therefore, 16g of oxygen gas contains approximately 6.022 x 10^23 oxygen atoms.
If you know the density of oxygen and the molar mass of oxygen you can divide the two in order to find the molar volume of oxygen. (L/mol) Oxygen has a density of 1.429 g/L and a molar mass of 32.00 g/mol. (Just remember that the molar mass of oxygen, chemical formula of 0 2, comes straight from the Periodic Table.) So, divide: 1.429 g/L / 32.00 g/mol = 22.393 L/mol. The "g" unit cancells out and you're left with L/mol which is your molar mass. Compare that with 22.4 L/mol which is the accepted molar volume for an ideal gas, derived from the ideal gas law: pv=nRt. However, because most gases do not behave ideally there is a slight discrepancy.
Molecular mass of O2 = 2(16.0) = 32.0
Amount of O2 = 16/32.0 = 0.50mol
1 mol of O2 contains 6.02 x 1023 molecules (avogadro constant).
In one O2 molecule there are two O atoms.
Thus, number of atoms present = 2 x 0.50 x 6.02 x 1023 = 6.02 x 1023
16.0 grams of O2 is equal to 0.5 moles, which has a volume of 11.2 liters at STP. 16.0 moles of O2 has a volume of ?æ358 liters.
What is the volume of 1.2 moles of oxygen gas 02 at standard temperature and pressure
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What is the mass in grams of 1mole of oxygen?
The mass of 2.000 mol of oxygen atoms is 32.00 grams.
How many grams of oxygen are contained in 18g of water?
The molar mass of water(H2O)=18((1*2)+16)The no. of moles(n) of water in 18 g of water=mass/molar mass=18 g/ 18 g mol-1 =1 molThe no. of molecules of water in 18 of water=n*Avogadro no. =1 mol*6.022*1023 mol-1 =6.022*1023The no. of atoms of oxygen in one mole of water=1 molThe no. of atoms of oxygen in 6.022*1023mol of water= 6.022*1023
How many oxygen atoms are present in 40.0 grams of oxygen gas?
There are approximately 0.625 moles of oxygen gas in 40.0 grams. Since the formula for oxygen gas is O2, there are 0.625 moles x 2 = 1.25 moles of oxygen atoms. Therefore, there are approximately 1.25 x 6.022 x 10^23 = 7.53 x 10^23 oxygen atoms in 40.0 grams of oxygen gas.
When 46g of sodium were exposed to dry air 62g of sodium oxide formed how many grams of oxygen from the air were used?
To find the amount of oxygen used, we need to consider the difference in mass between sodium and sodium oxide. The mass increase is 16g (62g - 46g) which corresponds to the amount of oxygen used from the air. Therefore, 16g of oxygen from the air were used.
How many grams of iron must be added to 16 grams of oxygen to equal 44 grams of iron 3 oxide?
Iron(III) oxide is composed of one iron atom and three oxygen atoms. Therefore, if we have 44 grams of iron(III) oxide, we can calculate the mass of iron by subtracting the mass of oxygen. 44g - 16g (mass of oxygen) = 28g of iron is needed to combine with 16g of oxygen to form 44g of iron(III) oxide.
How many atoms are present in 16g og Oxygen?
One mole of oxygen has a mass of 16 grams and contains 6.022 x 10^23 oxygen atoms. Therefore, 16 grams of oxygen will also contain 6.022 x 10^23 oxygen atoms.
How many atoms are present in 16g of O?
1 mole of O has a mass of 16g and contains 6.022 x 10^23 atoms (Avogadro's number). Therefore, 16g of O would contain the same number of atoms, which is 6.022 x 10^23 atoms.
How many atoms in 16g of O and 8g of S?
In 16g of O, there are approximately 3.02 x 10^23 atoms, as the atomic mass of oxygen is 16 g/mol. In 8g of S, there are approximately 6.02 x 10^23 atoms, as the atomic mass of sulfur is 32 g/mol.
If 16g of oxygen contains 1 mole of oxygen atoms calculate the mass of one atom of oxygen in grams?
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How many atoms are in 16 grams of oxygen?
1mol O = 16.0g (rounded to 1 decimal place) 1mol O atoms = 6.022 x 1023 atoms 16g O x 1mol/16g = 1mol O 1mol O x 6.022 x 1023atoms/mol = 6.022 x 1023 atoms O
What is the mass in grams of 1mole of oxygen?
The mass of 2.000 mol of oxygen atoms is 32.00 grams.
How many grams of oxygen are contained in 18g of water?
The molar mass of water(H2O)=18((1*2)+16)The no. of moles(n) of water in 18 g of water=mass/molar mass=18 g/ 18 g mol-1 =1 molThe no. of molecules of water in 18 of water=n*Avogadro no. =1 mol*6.022*1023 mol-1 =6.022*1023The no. of atoms of oxygen in one mole of water=1 molThe no. of atoms of oxygen in 6.022*1023mol of water= 6.022*1023
How many atoms in 16g of O?
The Avogadro number: 6,02214129(27)×1023.
How many number of moles of carbon dioxide that are contain 16g of oxygen?
To calculate the moles of carbon dioxide, we first need to determine the number of moles of oxygen in 16g. Using oxygen's molar mass of 16 g/mol, we find that there is 1 mole of oxygen in 16g. Since one mole of oxygen reacts with one mole of carbon dioxide in the balanced equation, there will also be 1 mole of carbon dioxide formed.
How many atoms are present in 16g of O and 8g of S?
To calculate the number of atoms present in a given mass of a substance, we need to use the concept of molar mass and Avogadro's number. The molar mass of oxygen (O) is approximately 16 g/mol, and the molar mass of sulfur (S) is approximately 32 g/mol. For oxygen: 16g / 16 g/mol = 1 mol of O. 1 mol of O contains 6.022 x 10^23 atoms (Avogadro's number). Therefore, 16g of O contains 6.022 x 10^23 atoms. For sulfur: 8g / 32 g/mol = 0.25 mol of S. 0.25 mol of S contains 0.25 x 6.022 x 10^23 atoms = 1.5055 x 10^23 atoms. Therefore, there are approximately 6.022 x 10^23 atoms in 16g of oxygen and approximately 1.5055 x 10^23 atoms in 8g of sulfur.
How many moles of atoms are there in 3.968x1023 atoms Mg?
Divide that number by Avogadro's number: 3.968x10(23) / 6.02x10(23) = 0.659mol Mg, which would be about 16g.
How many oxygen atoms are present in 40.0 grams of oxygen gas?
There are approximately 0.625 moles of oxygen gas in 40.0 grams. Since the formula for oxygen gas is O2, there are 0.625 moles x 2 = 1.25 moles of oxygen atoms. Therefore, there are approximately 1.25 x 6.022 x 10^23 = 7.53 x 10^23 oxygen atoms in 40.0 grams of oxygen gas.
