One mole of any mono-atomic element contains (by definition) 6.022*10+23 atoms. please calculate from there by multiplying - 11,14.1023 atoms.
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There are approximately 1.11 x 10^24 atoms in 1.85 moles of Fe. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles of Fe.
To determine the number of moles of Fe that can be made from 25 moles of Fe2O3, you need to write the balanced chemical equation for producing O2 from Fe2O3. 2Fe2O3 = 4Fe + 3O2, which means that 2 moles of Fe2O3 will produce 4 moles of Fe and 3 moles of O2 . Set up a proportion. 3 moles of O2 ÷ 2 moles of Fe2O3 = x moles of O2 ÷ 25 moles of Fe2O3 Cross multiply and divide. 3 moles of O2 * 25 moles of Fe2O3 ÷ 2 moles of Fe2O3 = 37.5 moles of O2 produced.
There are 3.01 x 10^24 atoms in 5.0 moles of Fe. This is calculated using Avogadro's number (6.022 x 10^23 atoms/mol) multiplied by the number of moles.
1,495
To find the number of atoms in 55.8 grams of Fe, you need to first calculate the moles of Fe using the molar mass (55.85 g/mol). Then you can use Avogadro's number (6.022 x 10^23) to convert moles to atoms.
In one molecule of iron (III) oxide (Fe2O3), there are a total of 5 atoms: 2 iron (Fe) atoms and 3 oxygen (O) atoms.