How does rubidium form an ion?

Answer 1

in the same way as sodium/potassium forms an ion.

Lithium has an electron configuration of 2,1

Sodium has an electron configuration of 2,8,1,

Potassium has an electron configuration of 2,8,8,1

Rubidium has an electron configuration of 2,8,8,18,1

Caesium has the electron configuration of 2,8,8,18,18,1

Notice in all cases the last number is '1'. This represents the outer most electron, shell with one electron. Since it is the outer most electron and is shielded by energy shells of electrons from the nucleus, this outer most electron is not strongly held to the atom. The atom readily releases this outermost electron , and the process is called ionisation.

Chemically it is represented by the formula

M(g) = M^+(g) + e^-

NB

'M' is an ATOM

'M^+' is an ION (Not an atom).

Answer 2

Rubidium forms a +1 cation (Rb+) by losing one electron to achieve a stable electron configuration. Rubidium has one valence electron in its outermost shell, so by losing this electron, it becomes a cation.

Answer 3

When rubidium (Rb, #37) forms an ion, it loses its one valence electron. Once it loses this electron, its protons (37) outnumber its electrons (36), which gives it a charge of +1.

Answer 4

Rubidium loses one electron to form Rb+ and achieve the electronic configuration of Krypton, a noble gas, [Ar] 3d10 4s2 4p6

Answer 5

It loses an electron to form Rb+ which has the electronic configuration of krypton

Answer 6

Rubidium ionizes by losing its one valence electron. Its charge is therefore +1, and the ion is isoelectronic with Kr.

Answer 7

Rubidium is a metal in group 1. It has one electron in its outermost energy level so it reacts by losing this electron to form an ion with a 1+ charge.

Answer 8

Losing an electron rubidium become the cation Rb+.

Answer 9

Yes; this compound is rubidium chloride, RbCl.

Answer 10

Rubidium forms the Rb+ ion.