How do you prepare 0.1M tris HCl buffer of pH 8?

Answer 1

Tris(hydroxymethyl)aminomethane (Tris) has a molecular weight of 121.14 g/mol.

50 mM = 0.050 mol/L (x 121.14 g/mol) = 6.057 g/L

To prepare a 1L solution first weigh out 6.057 g Tris

Add roughly 70% of final volume of water (i.e. 700 mL)

Use a pH-meter to measure the pH of the solution

Lower the pH of the solution to 7.2 using undiluted HCl

Use a measuring cylinder or volumetric flask to make the volume up to 1000 mL

If you add too much HCl you need to add more Tris and then recalculate the amount of water that you need add. In this case, every 1 g of Tris requires 165 mL of water to be added.

Answer 2

for 1 litre, ie. 500ml,

(moleular wt)/1000x(volume)500mlx50mM/1000=x gram

add the x gram of Tris in about450ml of water, adjust the pH to 8 with HCl and make it up to 500ml!

You can find the molecular wt of Tris in the its box!

Answer 3

To prepare a 0.1M Tris-HCl buffer of pH 8, you would dissolve the appropriate amounts of Tris base and HCl in water while monitoring the pH using a pH meter. Adjust the pH to 8 by adding a small amount of acid or base as needed. Make sure to use the Henderson-Hasselbalch equation to calculate the ratio of Tris base to Tris-HCl needed to achieve the desired buffer strength and pH.

Answer 4

Dissolve 2.71 gm of potassium dihydrogen phosphate in 100 ml distilled water.

Adjust the pH 7.4 by using 0.02 M Sodium hydroxide.

Make the final volume upto 1 liter. Label as 50mM phosphate buffer.

2.71 gm makes the buffer 20 mM, right?

6.8 gm makes the buffer 50 mM.

Answer 5

1M Tris-HCl, pH 8

Tris base (MW 121.14g)

To make the 0.02M

1mol = 121.14g

0.02 moles= x

x= 0.02mol x 121.14g/ 1mol

=2.4228g

therefore to make a 0.02M solution weigh out 2.4228g and dissolve in 800ml

of distilled water. adjust the pH to 8 with conc HCL and make up to 1000ml (1L)

if the required volume is 100mls

1000ml------->2.4228g

100ml------->0.24228g (apply the same procedure by first dissolving in 90 mls)

Answer 6

Add 12.1 grams of Tris-HCL base (powder) to 800ml of distilled water. Place in a stirrer and allow all the salt to dissolve. Adjust the pH to 8.0. Make up the volume to 1000ml.

The final solution will be 1000ml of 0.1M Tris-HCL of pH 8.0

Answer 7

In order for one to do this one might ask a college professor of Chemistry or Science. One will have to adjust the water in order to do this but it might be best explained by a teacher.