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To prepare a 0.02 M solution of HCl, you would need to dilute concentrated HCl solution with a calculated amount of water. For example, to prepare 1 liter of 0.02 M HCl solution, you would mix 4.2 ml of concentrated HCl (12 M) with 995.8 ml of water. Always add acid to water slowly and with stirring to avoid splattering.
0.02M=20mM(multiply x1000)
From a 1M stock HCL I shall prepare 100ml of 20mM HCl by the following equation
V1N1=V2N2
100mlx20mM=1000mMx"V2"
V2=100x20/1000
=2ml.
So add 2ml of 1M stock HCl plus 98ml of water to make 100ml of 0.02M HCL; this formula applies for any amount/concentration of solution. Hope this help you.
12*x=2*100
x=2*100/12
=3.56
so 3.56ml of concentrated HCl has to taken and make up to 100ml
1.7 ml to 100
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How do you prepare 1N Hcl solution Dont tell in gL how much ml is required?
To prepare 1N HCl solution, you need to dilute concentrated HCl (usually 37% w/w) with water to get the desired concentration. For a 1N HCl solution, you would mix 1 part of concentrated HCl with 9 parts of water (ratio of 1:9). The volume needed would depend on the final volume required and the concentration of the concentrated HCl you start with.
What is the molarity of the solution produced when 85.6 g of hydrochloric acid HCl is dissolved in sufficient water to prepare 0.385 L of solution?
To find the molarity, first calculate the number of moles of HCl present: 85.6 g / 36.46 g/mol = 2.35 mol Then, divide the moles by the volume in liters: Molarity = 2.35 mol / 0.385 L ≈ 6.10 M. Thus, the molarity of the solution is approximately 6.10 M.
Prepare 500ml of 0.12N HCL solution?
To prepare 500ml of 0.12N HCl solution, you will need to dilute a concentrated hydrochloric acid solution. To do this, measure out 2.5ml of concentrated HCl (37% w/w) and dilute it to 500ml with distilled water. Be sure to wear appropriate safety equipment and handle the acid with caution.
What volume of stock solution would be required to make a 150 mL solution of 0.50 M HCl from a 2.00 M HCl stock solution?
To find the volume of the 2.00 M HCl stock solution needed, we use the formula M1V1 = M2V2. Rearranging for V1 gives us V1 = (M2 * V2) / M1, where M2 is the desired concentration (0.50 M), V2 is the final volume (150 mL), and M1 is the stock concentration (2.00 M). Plugging in the values gives V1 = (0.50 M * 150 mL) / 2.00 M = 37.5 mL. You will need 37.5 mL of the 2.00 M HCl stock solution to make a 150 mL solution of 0.50 M HCl.
How many moles of HCl are consumed in a reaction of 25 mL of 4 M is added to excess CaCO3?
To find the moles of HCl consumed, we first calculate the moles of HCl in 25 mL of 4 M solution: 25 mL * 4 mol/L = 100 mmol. Since CaCO3 is in excess, it reacts with all the HCl.
How many ml of 6.00m hcl are needed to prepare 1000 ml of a 100m hcl?
100 M HCl don't exist.
How to prepare 3 M methanolic HCL?
make sure to sudy it alot
What volume of 3.0 M HCl sould be obtained to prepare 100 mL of 1.0 M HCL?
To prepare 100 mL of 1.0 M HCl from a 3.0 M stock solution, you can use the formula: (M_1V_1 = M_2V_2). Solving for V1: (3.0 M)(V1 mL) = (1.0 M)(100 mL), thus V1 = 33.3 mL. So, you would need to measure out 33.3 mL of the 3.0 M HCl solution and then dilute it to 100 mL to obtain 1.0 M HCl.
What volume of a 1.50 M HCl solution should you use to prepare 2.00 L of a 0.100 M HCl solution?
To prepare a 0.100 M HCl solution from a 1.50 M HCl solution, you need to use the dilution formula, which is M1V1 = M2V2. You would need to use (V_1 = \frac{M_2V_2}{M_1}) to calculate the volume needed. Plugging in the values, you would need to use ( V_1 = \frac{0.100 M \times 2.00 L}{1.50 M} = 0.133 L or 133 mL) of the 1.50 M HCl solution.
How do prepare 0.1m methanolic hcl?
To prepare 0.1M methanolic HCl, you would first need to calculate the volume of concentrated HCl needed to make the solution. Since methanol is the solvent, you would mix the calculated volume of concentrated HCl with methanol in a volumetric flask and dilute to the desired final volume. It is important to handle concentrated HCl with care due to its corrosive nature and always add acid to solvent, not the other way around, to avoid splattering.
How to prepare HCL solution?
To prepare a hydrochloric acid (HCl) solution, you can dilute concentrated hydrochloric acid with water. Always add the acid to water slowly while stirring, never add water to acid, as it can cause splattering. Be sure to wear appropriate protective gear and work in a well-ventilated area when handling HCl.
How do you prepare a 0.0001 M soulution HCL using 0.1 M of HCl?
you need to make 1000 times dilutions, this could be done in multi-steps: transfer 1 ml 0.1 M HCl into 100 ml volumetric flask and complete volume with water --------(1) from solution (1) transfer 2 ml into 20 ml volumetric falsk and complete volume with water, this is 0.0001 M HCL.
What volume of 25 M HCl must be diluted to prepare 1.5 L of 4.1x10-2 M HCl?
To find out how much 25 M HCl must be diluted to prepare 1.5 L of 4.1x10-2 M HCl, you can apply the dilution formula: M1V1 = M2V2. Plug in the values to find the initial volume of 25 M HCl that needs to be diluted to prepare 1.5 L of 4.1x10-2 M HCl.
How would one prepare 10 ml of a 25 M HCI solution if 1 M HCI was available?
To prepare a 10 ml of a 25 M HCl solution, you would need to dilute the 1 M HCl solution by a factor of 25. You will need 0.25 ml of the 1 M HCl solution and 9.75 ml of solvent (usually water) to make a total volume of 10 ml for the 25 M HCl solution.
Why you use 85 ml Conc HCl for 1 M HCl?
To prepare 1 M hydrochloric acid (HCl) solution, you usually need to dilute concentrated HCl solution (~35-37% HCl) with water in a specific ratio. The specific volume of concentrated HCl needed depends on its concentration and the final volume of the 1 M solution you want to make. In this case, 85 ml of concentrated HCl is likely to be the volume needed to make 1 L of 1 M HCl solution.
How many mL of HCL do you measure to prepare a liter of 0.5N HCL?
To prepare a liter of 0.5N HCl solution, you would measure 50 mL of concentrated hydrochloric acid (37% HCl by mass) and dilute it to 1 liter with distilled water.
How would you prepare 17.2 L of a 3.8 M HCl solution?
To prepare a 3.8 M HCl solution, you would need to measure 65.36 mol of HCl. You can then dilute this to a final volume of 17.2 L using water. Make sure to wear appropriate protective gear and handle the concentrated HCl solution with caution, as it is a strong acid.
