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To make a 0.1N solution of ferrous ammonium sulfate, you first need to calculate the molecular weight of the compound. Then, you can dissolve the calculated amount of ferrous ammonium sulfate in the appropriate volume of water to prepare the desired concentration. Finally, make adjustments to the pH if needed.
To make a 0.25 M solution of ammonium sulfate from a stock solution of 6 M, you would need to dilute the stock solution. The dilution equation is C1V1 = C2V2 where C1 and V1 are the concentration and volume of the stock solution, and C2 and V2 are the concentration and volume of the final solution. You would need to set up this equation to calculate the volume of the stock solution needed and then convert that volume to grams using the molar mass of ammonium sulfate.
Yes, ammonium sulfate is polar. It consists of an ammonium cation (NH4+) and a sulfate anion (SO4^2-), which have charged components that make the compound polar.
To make a 0.25M solution of ammonium sulfate at a concentration of 6M, you would need to dilute the 6M solution. Assuming you have 1 liter of the 6M solution, you can calculate the volume needed for dilution using the formula: (C1V1 = C2V2), where C1 = 6M, V1 = volume of the 6M solution (in liters), C2 = 0.25M, and V2 = total volume of the diluted solution (in liters). Once you have the volume, you can convert it to grams using the molar mass of ammonium sulfate.
When ferrous sulfate reacts with sodium hydroxide, a precipitate of ferrous hydroxide is formed. The balanced chemical equation for the reaction is FeSO4 + 2NaOH → Fe(OH)2 + Na2SO4. This reaction is a double displacement reaction where the cations and anions switch partners.
Aluminum sulfate reacts with ammonium hydroxide to form aluminum hydroxide and ammonium sulfate.