KO2 is potassium superoxide. It reacts with carbon dioxide to form potassium carbonate and oxygen. This reaction makes the potassium superoxide useful in a self-contained breathing devise. It can be used my mountaineers, divers, or anyone who needs or wants to breath under water. The amount of oxygen the devise would make would vary based on how much K02 is available.
The chemical formula of the ionic compound potassium oxide is K2O. This indicates that there are two potassium ions (K+) for every oxygen ion (O2-).
The chemical formula for an ionic compound of potassium and oxygen is K2O.
If is K2O (potassium oxide) it would be: K2O+H2SO4=K2SO4+H2O It could also form potassium bisulfate: K2O + 2 H2SO4 = 2 KHSO4 + H2O But I'm not sure if you are referring to potassium peroxide (K2O2) or superoxide (KO2)
The correct formula for the ionic compound formed between potassium and oxygen is K2O. Potassium is a Group 1 element with a +1 charge, while oxygen is a Group 16 element with a -2 charge. By balancing the charges, we get K2O as the formula for the compound.
A compound containing potassium and oxygen atoms would have a formula of K2O, and would be named potassium oxide. This is a binary ionic compound.
The chemical formula of potassium superoxide is KO2.
The balanced chemical equation for the reaction would be: 4KO2 + 2CO2 β 2K2CO3 + 3O2 Since the molar ratio between KO2 and O2 is 4:3, 0.400 mol of KO2 would produce: 0.400 mol KO2 * (3 mol O2 / 4 mol KO2) = 0.300 mol O2
KO2
For every 4 moles of KO2 consumed, 3 moles of O2 are produced. Since the molar mass of KO2 is 71.097 g/mol, 323.2 grams of KO2 is approximately 4.55 moles. Therefore, 3/4 * 4.55 = 3.41 moles of O2 are produced. This is equivalent to 6.83 grams of O2.
The balanced equation for KO2 + H2O is 2KO2 + 2H2O -> 2KOH + O2. This means that for every 2 moles of KO2 and H2O, you get 2 moles of KOH and 1 mole of O2.
Potassium superoxide (KO2) is used in submarines to generate oxygen. When KO2 reacts with water vapor in the air, it releases oxygen gas. This provides a source of breathable air for the crew in case of emergencies or when the submarine is submerged for extended periods.
The oxidation number for oxygen (O) in KO2 is -1. Since the overall charge of the compound is 0, the oxidation number of potassium (K) is +1.
Potassium Hydroxide (KOH) is a base. Bases contain hydroxide (OH) while acids contain hydrogen (H).
One mole of KO2 produces 1 mole of O2. The molar mass of KO2 is 71.1 g/mol and that of O2 is 32 g/mol. So, 8.5 g of O2 would require (8.5 g / 32 g/mol) x 71.1 g/mol = 18.95 grams of KO2.
When potassium and oxygen react, the most stable compound formed is potassium oxide (K2O). KO2 can be formed when there is an excess of oxygen present. In this case, oxygen binds to potassium to form potassium superoxide (KO2) instead of the normal oxide.
The minimum amount of KO2 required for the apparatus to produce enough oxygen for a 15-minute emergency exit depends on the flow rate of oxygen required by the user and the reactivity of KO2. Typically, a 500g cartridge of KO2 can provide enough oxygen for 15-30 minutes of use in emergency situations. It's essential to test the apparatus to determine the exact amount needed for 15 minutes.
K + o2 = ko2