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The groundstate for Sodium (11-Na) is:

1S2 , 2S2, 2P6, 3S1

If you count the ^powers you notice it'll sum to 11, when Sodium is excited the outermost electron (3S1) will be excited from the 3S shell to the next shell up which is the 3P shell.

The "core" electron configuration doesn't change so the first excited state is simply:

1S2 , 2S2, 2P6, 3P1

For the next excited state the electron that is now in the 3P shell will transition to the 4S shell before the 3D shell

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