Yes, it can, by displacing the Iodide
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Yes, liquid bromine can react with potassium iodide to form potassium bromide and elemental iodine. This reaction is a displacement reaction, where the more reactive element (bromine) displaces the less reactive element (iodine).
The word equation for the reaction between bromine and potassium iodide is: bromine + potassium iodide -> potassium bromide + iodine.
Yes, calcium chloride and potassium iodide can react with each other to form calcium iodide and potassium chloride. This reaction results in the exchange of ions between the two compounds.
Yes, chlorine will react with potassium bromide to form potassium chloride and bromine. This is a displacement reaction where the more reactive chlorine displaces bromine from potassium bromide.
Bromine does not react with aqueous potassium chloride because it is less reactive than chlorine. Chlorine is more electronegative than bromine and hence has a higher tendency to displace bromine from its compounds. Consequently, bromine remains unreactive in the presence of aqueous potassium chloride.
The amount of excess potassium iodide depends on the stoichiometry of the reaction between potassium iodide and copper sulfate. One equivalent of potassium iodide is needed to react with one equivalent of copper sulfate. Excess potassium iodide would be any amount added beyond this stoichiometric ratio.