The gram Atomic Mass of sodium is 22.9898, the formula of the least hydrated form of sodium phosphate is Na3PO4.10 H2O, and the gram formula unit mass of this sodium phosphate is 344.09. Therefore, the mass fraction of sodium in this sodium phosphate is 3(22.9898)/344.09 or about 0.20044, and the grams of sodium in 7.2 grams of this sodium phosphate is 1.44 grams of sodium, to the justified number of significant digits.
To calculate the number of grams of sodium in sodium phosphate, we need to know the molar mass of sodium phosphate (Na3PO4). The molar mass of Na3PO4 is 164.0 g/mol. Since there are 3 sodium atoms in one molecule of Na3PO4, the molar mass of sodium in Na3PO4 is 22.99 g/mol. Therefore, there are 7.2 g * (22.99 g/mol / 164.0 g/mol) = 1.01 grams of sodium in 7.2 grams of sodium phosphate.
To calculate the grams of sodium hydroxide present in the solution, first calculate the number of moles using the formula: moles = Molarity (M) x Volume (L). Then, use the molar mass of sodium hydroxide (NaOH) to convert moles to grams. The molar mass of NaOH is 40 g/mol. Thus, in this case, you have 0.3375 moles of NaOH and if you convert this to grams, it would be 13.5 grams.
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
To determine the number of moles of sodium carbonate in 2 grams of hydrated sodium carbonate, we first need to calculate the molar mass of Na2CO3·xH2O. Once we have the molar mass, we can use the formula: Moles = Mass / Molar mass. Given that hydrated sodium carbonate has the molar mass of Na2CO3·xH2O, we can determine the number of moles in 2 grams of the compound.
To calculate the mass of 4.00 moles of sodium, you can use the molar mass of sodium which is approximately 23 grams/mol. Therefore, 4.00 moles of sodium would have a mass of 4.00 moles * 23 grams/mole = 92 grams.
To calculate the number of sodium ions in 25.75 grams of sodium chloride, first find the molar mass of NaCl (58.44 g/mol). Divide the given mass by the molar mass to find the number of moles of NaCl (0.44 moles). Since each NaCl molecule contains one sodium ion, there are 0.44 moles of sodium ions in 25.75 grams of NaCl.
To calculate the number of moles in 10 grams of sodium phosphate (Na3PO4), we first need to determine the molar mass of Na3PO4, which is approximately 164.0 g/mol. Then, we can use the formula: moles = mass / molar mass. Therefore, for 10 grams of sodium phosphate, there would be approximately 0.061 moles present.
To calculate the mass in grams of sodium sulfate, we need to know the number of moles. Once we have the number of moles, we can multiply it by the molar mass to find the mass in grams. For example, if we have 2 moles of sodium sulfate, the mass would be 2 moles * 141.98 grams/mole = 283.96 grams.
To calculate the grams of sodium hydroxide present in the solution, first calculate the number of moles using the formula: moles = Molarity (M) x Volume (L). Then, use the molar mass of sodium hydroxide (NaOH) to convert moles to grams. The molar mass of NaOH is 40 g/mol. Thus, in this case, you have 0.3375 moles of NaOH and if you convert this to grams, it would be 13.5 grams.
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
To find the amount of sodium hydroxide needed to react with 150g of phosphoric acid, you first need to determine the balanced chemical equation between sodium hydroxide and phosphoric acid. From there, you can use stoichiometry to calculate the amount of sodium hydroxide needed.
Sodium phosphate is Na3PO4, which means each molecule of sodium phosphate is four atoms of oxygen bound to a central phosphorus atom, with three sodium atoms arranging themselves randomly to three of the oxygen atoms. Sodium phosphate is Na3PO4, which means each molecule of sodium phosphate is four atoms of oxygen bound to a central phosphorus atom, with three sodium atoms arranging themselves randomly to three of the oxygen atoms.
To determine the number of moles of sodium carbonate in 2 grams of hydrated sodium carbonate, we first need to calculate the molar mass of Na2CO3·xH2O. Once we have the molar mass, we can use the formula: Moles = Mass / Molar mass. Given that hydrated sodium carbonate has the molar mass of Na2CO3·xH2O, we can determine the number of moles in 2 grams of the compound.
To determine the number of atoms in 46.0 grams of sodium, you first need to calculate the number of moles of sodium present. With the molar mass of sodium being 22.99 g/mol, you can divide the given mass by the molar mass to find the number of moles. Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to atoms by multiplying the number of moles by Avogadro's number.
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution
To calculate the mass of 4.00 moles of sodium, you can use the molar mass of sodium which is approximately 23 grams/mol. Therefore, 4.00 moles of sodium would have a mass of 4.00 moles * 23 grams/mole = 92 grams.
To calculate the number of sodium ions in 25.75 grams of sodium chloride, first find the molar mass of NaCl (58.44 g/mol). Divide the given mass by the molar mass to find the number of moles of NaCl (0.44 moles). Since each NaCl molecule contains one sodium ion, there are 0.44 moles of sodium ions in 25.75 grams of NaCl.
To find the number of moles in 42.5 grams of sodium chloride (NaCl), you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass by the molar mass to get the number of moles. In this case, 42.5 grams divided by 58.44 g/mol is approximately 0.727 moles of sodium chloride.