When gold(III) sulfate and barium chloride react, a double displacement reaction occurs. The products are barium sulfate (a white solid) and gold(III) chloride. Gold(III) chloride is a yellow solid that is sparingly soluble in water.
When copper II sulfate reacts with barium chloride, copper II chloride and barium sulfate are formed. The balanced chemical equation for this reaction is CuSO4 + BaCl2 -> CuCl2 + BaSO4.
When aluminum sulfate reacts with barium chloride, aluminum chloride and barium sulfate are formed. Aluminum chloride is a white solid, while barium sulfate is a white precipitate that forms in the reaction mixture. The balanced chemical equation for this reaction is Al2(SO4)3 + 3BaCl2 -> 2AlCl3 + 3BaSO4.
The ionic equation for barium chloride (BaCl2) plus copper sulfate (CuSO4) is Ba2+ + SO4^2- β BaSO4(s) and Cu2+ + 2Cl- β CuCl2. This suggests the formation of a white precipitate of barium sulfate and copper chloride in solution.
When barium chloride reacts with sodium sulfate, barium sulfate and sodium chloride are formed. This is known as a double displacement reaction. The balanced chemical equation for this reaction is BaCl2 + Na2SO4 -> BaSO4 + 2NaCl.
This word equation is incorrect because it does not follow the law of conservation of mass. The equation should be: calcium chloride plus magnesium sulfate yields barium sulfate plus magnesium chloride.
The balanced equation for the reaction between barium sulfate (BaSO4) and calcium chloride (CaCl2) is BaSO4 + CaCl2 -> BaCl2 + CaSO4. This reaction forms barium chloride (BaCl2) and calcium sulfate (CaSO4) as products.
The insoluble salt barium sulfate is obtained.
Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]Ba2++ SO42- --> BaSO4
The balanced chemical equation for barium chloride (BaCl2) reacting with potassium sulfate (K2SO4) is: BaCl2 + K2SO4 -> BaSO4 + 2KCl. This reaction forms barium sulfate (BaSO4) and potassium chloride (KCl).
When gold(III) sulfate and barium chloride react, a double displacement reaction occurs. The products are barium sulfate (a white solid) and gold(III) chloride. Gold(III) chloride is a yellow solid that is sparingly soluble in water.
When copper II sulfate reacts with barium chloride, copper II chloride and barium sulfate are formed. The balanced chemical equation for this reaction is CuSO4 + BaCl2 -> CuCl2 + BaSO4.
Ooh. Somebody doesn't like doing their chem homework. Luckily I just happened to do that exact same equation. 1 BaCl2 +1 Na2S --> 2 NaCl(Salt! :D) +1 BaS
When barium chloride (BaCl2) is mixed with sodium sulfate (Na2SO4), barium sulfate (BaSO4) is formed as a white, insoluble precipitate. This white precipitate appears milky when the two solutions are mixed because it scatters light due to its small particle size and makes the solution appear cloudy.
barium chloride plus sodium sulphate yields barium sulphate plus sodium chloride
When aluminum sulfate reacts with barium chloride, aluminum chloride and barium sulfate are formed. Aluminum chloride is a white solid, while barium sulfate is a white precipitate that forms in the reaction mixture. The balanced chemical equation for this reaction is Al2(SO4)3 + 3BaCl2 -> 2AlCl3 + 3BaSO4.
The ionic equation for barium chloride (BaCl2) plus copper sulfate (CuSO4) is Ba2+ + SO4^2- β BaSO4(s) and Cu2+ + 2Cl- β CuCl2. This suggests the formation of a white precipitate of barium sulfate and copper chloride in solution.