Do you want that for Monopotassium phosphate, dipotassium phosphate, or tripotassium phosphate? --------------------------------- To clarify for the previous answerer, ionic compounds inherently don't use the mono-, di-, or tri- system used for molecular compounds. Instead, when a cation and an anion is supplied, the ionic compound assumes the number of cations and anions that will generate a neutral ionic compound. In this case, since K is 1+ and PO4 is 3-, the compound potassium phosphate always refers to K3PO4. Therefore: 3AgNO3 + K3PO4 -> 3KNO3 + Ag3PO4
The Balanced equation for Silver Nitrate and Potassium Chloride is:
AgNO3 + kCl --> AgCl+ KNO3 (silver chloride and potassium nitrate)
This equation is balanced because the number of atoms of the elements on both sides are the same.
The balanced equation for the reaction between silver nitrate (AgNO3) and potassium iodide (KI) is:
2AgNO3 + 2KI -> 2AgI + 2KNO3
Balanced:
AgNO3 + KI ----> KNO3 + AgI
Silver Potassium Cyanide = AgK(CN)2........ Potassium Carbonate = K2CO3........ Potassium Hydroxide = KOH........ Potassium Cyanide = KCN
Silver nitrate + potassium iodide -> silver iodide + potassium nitrate
AgNO3 + KI -----> AgI + KNO3
Silver thiocynate is formed, AgNO3 + KSCN ------> AgSCN + KNO3
2AgNO3 + K2CrO4 -> Ag2CrO4 + 2KNO3
AgNO3 + KBr -----> AgBr + KNO3
AgNO3 + KBr
The symbol equation for silver nitrate solution and potassium iodide is: AgNO3(aq) + KI(aq) -> AgI(s) + KNO3(aq).
The ionic equation for the reaction between silver nitrate (AgNO3) and potassium iodide (KI) is: Ag+ + I- → AgI(s). This equation represents the formation of silver iodide as a solid precipitate.
Silver nitrate solution and potassium iodide solution can be mixed to form silver iodide due to a double displacement reaction where the silver ions from silver nitrate react with the iodide ions from potassium iodide to form insoluble silver iodide precipitate. The balanced chemical equation for this reaction is: AgNO3 (aq) + KI (aq) → AgI (s) + KNO3 (aq).
The chemical equation for the reaction between lead nitrate (Pb(NO3)2) and potassium iodide (KI) to form lead iodide (PbI2) and potassium nitrate (KNO3) is: Pb(NO3)2 + 2KI → 2KNO3 + PbI2
The balanced symbol equation between fluorine and potassium iodide is: 2KI + F2 --> 2KF + I2
The balanced equation for the reaction between potassium iodide (KI) and lead(II) nitrate (Pb(NO3)2) to produce potassium nitrate (KNO3) and lead(II) iodide (PbI2) is: 2KI + Pb(NO3)2 → 2KNO3 + PbI2
When silver nitrate reacts with potassium iodide, a precipitation reaction occurs where silver iodide is formed. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3. The silver iodide formed will appear as a yellow solid precipitate.
The molecular equation for the reaction between silver nitrate (AgNO3) and potassium iodide (KI) is: AgNO3 + KI → AgI + KNO3. This reaction forms silver iodide (AgI) and potassium nitrate (KNO3).
The symbol equation for silver nitrate solution and potassium iodide is: AgNO3(aq) + KI(aq) -> AgI(s) + KNO3(aq).
The ionic equation for the reaction between silver nitrate (AgNO3) and potassium iodide (KI) is: Ag+ + I- → AgI(s). This equation represents the formation of silver iodide as a solid precipitate.
The chemical reaction between lead nitrate and potassium iodide produces lead iodide and potassium nitrate. The balanced chemical equation is: 2Pb(NO3)2 + 2KI -> 2PbI2 + 2KNO3
A yellow precipitate of lead(II) iodide is formed, according to the following balanced chemical equation: Pb(NO3)2 + 2KI -> PbI2 + 2KNO3
When silver nitrate and potassium iodide are combined, they undergo a double displacement reaction. Silver iodide is formed as a yellow precipitate, while potassium nitrate remains in solution. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3.
Silver nitrate solution and potassium iodide solution can be mixed to form silver iodide due to a double displacement reaction where the silver ions from silver nitrate react with the iodide ions from potassium iodide to form insoluble silver iodide precipitate. The balanced chemical equation for this reaction is: AgNO3 (aq) + KI (aq) → AgI (s) + KNO3 (aq).
A chemical reaction occurs where iron III iodide is formed and potassium nitrate is produced as a byproduct. The balanced chemical equation for this reaction is 2KI + Fe(NO3)3 -> 2KNO3 + FeI3. Iron III iodide is a dark brown solid, whereas potassium nitrate remains in solution.
The chemical equation for the reaction between lead nitrate (Pb(NO3)2) and potassium iodide (KI) to form lead iodide (PbI2) and potassium nitrate (KNO3) is: Pb(NO3)2 + 2KI → 2KNO3 + PbI2
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2