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The balanced equation for this decomposition reaction is 2 H2O2 -> 2 H2O + O2.

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The balanced chemical equation for the decomposition of hydrogen peroxide (H2O2) into water (H2O) and oxygen gas (O2) is: 2 H2O2 → 2 H2O + O2.

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10mo ago
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Q: Balance h2o2 h2o o2
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What the balance of H2O2 H2O O2?

The balanced chemical equation for the decomposition of hydrogen peroxide (H2O2) into water (H2O) and oxygen gas (O2) is: 2 H2O2 -> 2 H2O + O2. This means that for every 2 moles of hydrogen peroxide, 2 moles of water and 1 mole of oxygen are produced.


What enzyme break down h2o2 to h2o and o2?

Catalase is the enzyme that breaks down hydrogen peroxide (H2O2) into water (H2O) and oxygen (O2). It helps protect cells from damage caused by reactive oxygen species.


Which substance is the substrate in the equation 2 H2O2 ------- 2 H2O plus o2?

Hydrogen peroxide (H2O2) is the substrate in the given equation. It is broken down into water (H2O) and oxygen (O2) by the enzyme catalase.


What is the balanced equation for H2O2 when it reacts to form gas and H2O?

I think what you are thinking of is the decomposition of Hydrogen peroxide, which has the equation: 2H2O2 --> O2 + 2H2O which when balanced then equals 8. 2(H2O2) --> 2H2O +O2 |4*2|=8 -->|3*2|=6 +2= 8 That is the entire equation completed and balanced. Hope it helped!


The equlibrium constant for the reaction below is 0.62 At equlibrium O2 equals 0.40 and H2O equals 0.20 What is the equlibrum concentration of H2O2?

Using the equilibrium constant expression, (K = \frac{[products]}{[reactants]}), we can set up the equation as (0.62 = [H2O2] / ([O2] * [H2O])). Plugging in the given values, we get (0.62 = [H2O2] / (0.4 * 0.2)). Solving for [H2O2], we find the equilibrium concentration of H2O2 to be 0.62 * 0.4 * 0.2 = 0.0492.