The balanced equation for this decomposition reaction is 2 H2O2 -> 2 H2O + O2.
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The balanced chemical equation for the decomposition of hydrogen peroxide (H2O2) into water (H2O) and oxygen gas (O2) is: 2 H2O2 → 2 H2O + O2.
The balanced chemical equation for the decomposition of hydrogen peroxide (H2O2) into water (H2O) and oxygen gas (O2) is: 2 H2O2 -> 2 H2O + O2. This means that for every 2 moles of hydrogen peroxide, 2 moles of water and 1 mole of oxygen are produced.
Catalase is the enzyme that breaks down hydrogen peroxide (H2O2) into water (H2O) and oxygen (O2). It helps protect cells from damage caused by reactive oxygen species.
Hydrogen peroxide (H2O2) is the substrate in the given equation. It is broken down into water (H2O) and oxygen (O2) by the enzyme catalase.
I think what you are thinking of is the decomposition of Hydrogen peroxide, which has the equation: 2H2O2 --> O2 + 2H2O which when balanced then equals 8. 2(H2O2) --> 2H2O +O2 |4*2|=8 -->|3*2|=6 +2= 8 That is the entire equation completed and balanced. Hope it helped!
Using the equilibrium constant expression, (K = \frac{[products]}{[reactants]}), we can set up the equation as (0.62 = [H2O2] / ([O2] * [H2O])). Plugging in the given values, we get (0.62 = [H2O2] / (0.4 * 0.2)). Solving for [H2O2], we find the equilibrium concentration of H2O2 to be 0.62 * 0.4 * 0.2 = 0.0492.