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How many moles are in 150 grams what compound NaCl?
To calculate the number of moles in 150 grams of NaCl, you need to know the molar mass of NaCl, which is approximately 58.44 g/mol. You can then divide the given mass (150 grams) by the molar mass to get the number of moles. In this case, 150 g / 58.44 g/mol ≈ 2.57 moles of NaCl.
How many moles of (NH4)2S are there in 150 g of (NH4)2S?
To find the number of moles in 150 g of (NH4)2S, we first need to calculate the molar mass of (NH4)2S. The molar mass of (NH4)2S is 68.15 g/mol. Next, we use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 150 g / 68.15 g/mol, which is approximately 2.20 moles of (NH4)2S.
What mass of calcium bromide is needed to prepare 150.0 mL of a 3.50 M solution?
To calculate the mass of calcium bromide needed, you would first find the number of moles needed using the equation moles = Molarity * Volume (in liters). Then, you would use the molar mass of calcium bromide to convert moles to grams. The molar mass of calcium bromide is 199.89 g/mol.
How many grams of HCl can be prepared from 2.00 mol H2So4 and 150 g NaCl?
2NaCl + H2SO4 ----> 2HCl + Na2SO4 *molar mass of H2SO4 is 98.09g *molar mass of NaCl is 58.44g *molar mass HCl is is 36.46g Moles NaCl = 150 g / 58.44 = 2.56 The ratio between NaCl and H2SO4 is 2 : 1 so NaCl is the limiting reactant We would get 2.56 mol HCl => 2.56 mol x 36.46 g/mol = 93.3 g
What is the molarity of a solution made by dissolving 29.0 grams of NaCl in 150 ml of water?
The molar mass of NaCl is 58.44 g/mol, so 29.0 g is equivalent to 0.496 moles of NaCl. The volume of the solution is 0.150 L. Therefore, the molarity is calculated as 0.496 moles / 0.150 L = 3.31 M.
How many moles of atoms are in 150 g sulfur?
To find the number of moles of atoms in 150 g of sulfur, you need to first determine the molar mass of sulfur, which is about 32 g/mol. Then, you can use the formula moles = mass/molar mass. So, 150 g / 32 g/mol ≈ 4.69 moles of sulfur atoms.
If 20.0 mL of 150 M NaOH are used in a titration how many moles of NaOH are used?
To calculate the moles of NaOH used in the titration, multiply the volume (in liters) by the molarity. Converting 20.0 mL to liters (20.0 mL * 1 L/1000 mL = 0.020 L), the moles of NaOH used would be (0.020 L * 150 mol/L = 3.0 moles of NaOH).
How many moles are in 150 grams what compound NaCl?
To calculate the number of moles in 150 grams of NaCl, you need to know the molar mass of NaCl, which is approximately 58.44 g/mol. You can then divide the given mass (150 grams) by the molar mass to get the number of moles. In this case, 150 g / 58.44 g/mol ≈ 2.57 moles of NaCl.
How deep can moles dig?
150
How many moles of (NH4)2S are there in 150 g of (NH4)2S?
To find the number of moles in 150 g of (NH4)2S, we first need to calculate the molar mass of (NH4)2S. The molar mass of (NH4)2S is 68.15 g/mol. Next, we use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 150 g / 68.15 g/mol, which is approximately 2.20 moles of (NH4)2S.
How many atoms are present in 23.0 mol of Ti?
1 mol = 6,022 x 10^23 molecules of HI. So: 6,022E23 *0,3 = Your answer !
How many moles of sulfuric acid are present in 0.550 L of a 0.150 M sulfuric acid solution?
.150 M is the molarity of the solution, which is the number of moles per liter. So all you need to do is multiply the molarity by the number of liters. So .150 moles/liter x .550 L = .0825 moles
150 ml gas how many grms?
This depends on many things including temperature, pressure, number of moles and molecular weight or the density
You were hired by a laboratory to recycle 6 moles of silver ions You were given 150 g of copper How many grams of silver can you recover Is this enough copper to recycle 6 moles of silver ions?
No you need more copper
How many moles are there in 150 grams of Al(OH)3?
To determine the number of moles in 150 grams of Al(OH)3, we first need to calculate the molar mass of Al(OH)3: Aluminum (Al) has a molar mass of 26.98 g/mol, oxygen (O) has a molar mass of 16.00 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol. Molar mass of Al(OH)3 = 26.98 + 3(16.00) + 3(1.01) = 78.03 g/mol Now, we can calculate the number of moles: Number of moles = Mass (g) / Molar mass Number of moles = 150 g / 78.03 g/mol ≈ 1.92 moles.
How many moles of ammonium sulfate are in 150g sample?
To find the number of moles of ammonium sulfate in a 150g sample, you first need to calculate the molar mass of ammonium sulfate (NH4)2SO4, which is approximately 132.14 g/mol. Then, divide the given mass (150g) by the molar mass to get the number of moles, which would be approximately 1.14 moles.
What mass of NaCl is dissolved in 150 g of water in a .050 m solution?
To find the mass of NaCl present in the solution, we first need to calculate the number of moles of NaCl in the solution using the formula: moles = molarity x volume. The volume here is 150 g of water, which is approximately 150 mL. Therefore, the moles of NaCl in the solution would be (0.050 mol/L) x (0.150 L) = 0.0075 moles. The molar mass of NaCl is 58.44 g/mol, so the mass of NaCl in the solution is 0.0075 moles x 58.44 g/mol = approximately 0.44 g.
