No, N2 + 3H2 -> 2NH is the formula to make Ammonia, a gas that is present in urine.
The following is a schematic program. Details will depend on the language.n1 = 1output n1n2 = 1output n2.start loopn3 = n1 + n2output n3got enough numbers?if yes go to end elsen1
void main() { int i; float n1,n2; abc: printf("Enter two nos "); scanf("%f%f",&n1,&n2); printf("\n %f + %f = %f " ,n1,n2,n1+n2); printf("\n %f - %f = %f " ,n1,n2,n1-n2); printf("\n %f x %f = %f " ,n1,n2,n1*n2); printf("\n %f / %f = %f " ,n1,n2,n1/n2); printf("\npress 5 to make another calculation"); scanf("%d",&i); if (i==5) goto abc; }
the haber process the haber process the equation is N2 + 3H2 <--> 2NH3 the haber process! its easy, the equation is N2 + 3H2 <--> 2NH3
n2-1 and n2-4 are trivial cases because of n2-m2=(n-m)(n+m). So the only prime of the form n2-1 is 3 and of the form n2-4 is 5.
To convert 14 grams of N2 to NH3, you first need to balance the chemical equation for the reaction (N2 + 3H2 --> 2NH3) and calculate the molar ratio between N2 and NH3. Then you can use this ratio to determine the amount of NH3 produced.
Oh, dude, adding n squared plus n squared is like adding apples to apples, you know? It's just like, you take two n squared terms and you add them together to get 2n squared. It's not rocket science, man. Just double up those n squares and you're good to go.
The balanced chemical equation for nitrogen in pure form is N2(g) → N2(g). This represents the equilibrium reaction where nitrogen exists as diatomic molecules in the gaseous state.
P(x=n1,y=n2) = (n!/n1!*n2!*(n-n1-n2)) * p1^n1*p2^n2*(1-p1-p2) where n1,n2=0,1,2,....n n1+n2<=n
0 in N2
0 in N2
n x n = n2