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Is NH4I soluble

Updated: 9/7/2023

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∙ 11y ago

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yes

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∙ 11y ago

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Q: Is NH4I soluble

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Chemical formula for ammonium iodide?

The chemical formula for ammonium iodide is NH4I.

What is the name for the compound NH4I?

Ammonium Iodide

What is the compound name for NH4l?

The chemical formula NH4I is for ammonium iodide.

What is the oxidation number for NH4I?

The oxidation number for NH4+ is +1. Since the overall charge of NH4I is 0, the oxidation number for I has to be -1.

What is the formula for ammonium iodine?

The formula for ammonium iodide is NH4I. It consists of one ammonium ion (NH4+) and one iodide ion (I-).

Is NH4I a strong base?

No, NH4I is not a strong base. It is actually a salt formed from ammonium ion (NH4+) and iodide ion (I-) and does not dissociate completely in water to release hydroxide ions, which are characteristic of strong bases.

What is the formula for ammonium iodide silver nitrate?

The formula for the reaction between ammonium iodide (NH4I) and silver nitrate (AgNO3) is: 2NH4I + AgNO3 -> 2AgI + 2NH4NO3

What would NH4I plus H2O equals?

When NH4I is dissolved in H2O, it will dissociate into its ions, forming NH4+ and I- ions in the solution. This reaction is considered a dissociation reaction rather than a chemical reaction where new substances are formed.

What is the formula for the ionic compound formed from ammonium and iodide ions?

The formula for the ionic compound formed from ammonium and iodide ions is NH4I. Ammonium ion has a charge of +1 and iodide ion has a charge of -1, so they combine in a 1:1 ratio to form a neutral compound.

What is the formula for ammonium iodide?

The formula for ammonium iodide is NH4I. It is composed of one ammonium ion (NH4+) and one iodide ion (I-).

Is NH4l a compound?

NH4I is a compound consisting of ammonium cations (NH4+) and iodide anions (I-). It is named ammonium iodide.

What is the ionic formula for Ammonium iodide plus sodium hydroxide?

The reaction between ammonium iodide (NH4I) and sodium hydroxide (NaOH) will yield ammonia (NH3), sodium iodide (NaI), and water (H2O). The balanced chemical equation for this reaction is: 2NH4I + 2NaOH → 2NH3 + 2NaI + 2H2O

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