You don't need any calories to cool the water. They're already in the water,and in order to cool it, you have to let some of them out.1 calorie = 1 gram of water 1° C.From 60° C to 15° C = down 45 C.4.0 kg x 45° C = 4,000 grams x 45° C = 180,000 calories out of the water.A clever engineer could do something useful with that heat.
it depends if you try to lose calories its hot water but if your trying to cool yourself down you use cold water
Not all cool drinks contain alcohol
COOL
Ittakes 1 calorie for every degree C change of 1 gram of water answer: 100
To calculate the calories given off when 5 grams of water cool from 75°C to 25°C, you need to use the specific heat capacity of water. The specific heat capacity of water is 1 calorie/gram °C. First, calculate the temperature change: ΔT = 75°C - 25°C = 50°C Next, calculate the heat released using the formula: Q = m * c * ΔT Q = 5g * 1 calorie/gram °C * 50°C Q = 250 calories Therefore, 250 calories are given off when 5 grams of water cool from 75°C to 25°C.
Water have a very high heat capacity and that mean water can contain a lot of heat which resulted in the cooling effect. Remember ice is water in solid form.
Evaporation. In order to evaporate, the partial pressure of water vapor in the atmosphere must be lower than the equilibrium vapor pressure of water at the ambient temperature, and there must be a source of energy equivalent to the enthalpy of vaporization (for water, this is about 540 calories per gram). This is why you sweat: evaporation of a gram of water removes over half a kilocalorie of energy, which is enough to cool a liter of water by half a degree Celcius. It's also why sweating just makes you miserable on very humid days; the water can't evaporate so it doesn't actually cool you.
260 calories in a 1 3/4oz bag
Cool Water was created in 1948.
read the pakage, IDIOT!
Cool vItamin :D