Wiki User
β 7y ago75 g sodium chloride contain 29,75 g sodium.
Wiki User
β 9y agoJohn Merlino
If 75 grams of sodium reacts with 25 grams of chlorine how many grams of salt will be produced?
When sodium reacts with chlorine gas in a 1:1 molar ratio, the resulting compound is table salt (sodium chloride). The molar mass of sodium chloride is approximately 58.5 g/mol. Therefore, when you combine 1.5 grams of chlorine gas with sodium, you would produce approximately 58.5 grams of table salt.
The balanced chemical equation for the reaction between chlorine gas and sodium is: 2Na + Cl2 -> 2NaCl Using the equation, we can see that 1 mole of chlorine gas (Cl2) reacts with 2 moles of sodium (2Na). To calculate the mass of chlorine gas needed to react with 92 grams of sodium, first convert 92 grams of sodium to moles, then use the mole ratio from the balanced equation to find the moles of chlorine gas needed. Finally, convert the moles of chlorine gas to grams.
The answer is o,5 mol.
Since the reaction involves the formation of sodium chloride (NaCl), the molar ratio of sodium to chlorine is 1:1. Therefore, if 10 grams of sodium reacts to form 35 grams of NaCl, then 35 grams of chlorine is also needed for this reaction.
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
Sodium reacts with chlorine gas in a 1:1 molar ratio. Thus, for 2.00 mol of sodium, 2.00 mol of chlorine gas is required. The molar mass of chlorine gas is approximately 70.91 g/mol. Therefore, the mass of chlorine gas needed is 2.00 mol x 70.91 g/mol = 141.82 grams.
You would need 35.5 grams of chlorine to combine with 23 grams of sodium to make 58.5 grams of sodium chloride. This is based on the molar mass of sodium chloride, where one mole of sodium chloride is composed of one mole of sodium (23 grams) and one mole of chlorine (35.5 grams).
To calculate the amount of sodium chloride produced, we need to determine the limiting reactant. The balanced chemical equation for the formation of sodium chloride is 2Na + Cl2 -> 2NaCl. From the given masses of sodium and chlorine, we see that we have enough sodium to react completely with the chlorine. Therefore, all 46 grams of sodium will react to form 46 grams of sodium chloride.
To produce 10 grams of table salt (sodium chloride), you would need roughly 10 grams of chlorine gas. This is because the balanced chemical equation for the reaction between sodium and chlorine to form sodium chloride (table salt) is 2Na + Cl2 -> 2NaCl.
117 grams of sodium chloride (NaCl) is equivalent to 117 grams of chlorine gas because each molecule of NaCl contains one sodium atom and one chlorine atom.
Sodium has an atomic weight of 22.99 g/mol. Chlorine has an atomic weight of 35.45 g/mol. NaCl has an atomic weight of 58.44 g/mol. Therefore 92g of sodium would yield 233.86g of sodium chloride (NaCl).
The molar mass of sodium (Na) is 23 g/mol and the molar mass of chlorine (Cl) is 35.5 g/mol. Using the balanced chemical equation 2Na + Cl2 -> 2NaCl, we can see that 1 mole of Na reacts with 1 mole of Cl2 to produce 2 moles of NaCl. Therefore, 46 grams of Na reacts with 70 grams of Cl2 which is in excess. Thus, all the Na will react to form NaCl, resulting in 46 grams of sodium chloride being produced.