Copper losses are purely voltage-drop losses (I squared R) caused by the resistance of the windings, as opposed to hysteresis losses and eddy current losses (so-called iron losses), which are magnetic in nature. They are called copper losses whether the winding conductors are made of copper or not, by the way.
how to reduce copper losses in a transformer Copper losses are due to the resistance of the copper (or aluminum) windings. To reduce copper losses the transformer would have to be rewound with heavier gage wire.
The transformer will have the maximum efficiency.
Losses due to loading. As more load (more current) is put on a transformer, these losses will increase. They are often referred to as I2R (or I^2*R) losses.
Power transformers have both no load and full load losses. The key is copper wiring, as copper varies with the square inches of the secondary and primary currents.
Winding copper losses of a transformer can be measured in a short circuit test of a transformer. Impedance voltage is given to the primary and the secondary is often shortcircuited. (some times the reverse is done of this). Full load currents are made to flow in both primary and secondary circuits. This current flow heats up the 2 windings of the transformer. Power consumed at this time gives the transformer copper losses.
The transformer can be tested on open and short circuit to find the iron losses and copper losses separately, which uses a fraction of the power than having to run the transformer on full-load.
because of its losses i.e iron and copper losses. since iron loss depends on voltage (v)and copper loss depends on current(i).
Copper losses are directly related to loading of the transformer. Iron (core) losses are a result of magnetizing of the core of the transformer, and are relatively constant from no load to full load. With this in mind, it should be clear that the above statement is false. Maximum efficiency results with low core losses, and low copper losses. Copper losses cannot be helped, so it is important to minimize core losses to increase the efficiency of a transformer.AnswerYes, it is perfectly correct -well, with the proviso that transformers normally operate somewhat below full load and, so, are designed to achieve maximum efficiency somewhat below full load. A transformer's maximum efficiency does indeed occur when the copper losses and iron losses are equal. Unfortunately, the mathematical proof of this is too complicated to reproduce here, I suggest that you check out any reputable electrical engineering textbook.
For a single-phase transformer, maximum efficiency typically occurs at around 50-70% of the rated load. Operating the transformer at this load range minimizes losses and improves efficiency. Going below or above this range can decrease efficiency and increase losses in the transformer.
The copper losses, because they vary as the square of the secondary/primary currents.
there are several losses in a transformer that prevent it from attaining 100% efficiency. One is core loss, which can be divided into Hysteresis losses, Eddy currents and Magnetostriction loses. see for more details http://en.wikipedia.org/wiki/Transformer#Energy_losses
The no-load current of a transformer is the current which is drawn from the source at rated voltage and frequency even when no actual load current is being supplied.The no-load current is what must be drawn to overcome the inherent and unavoidable losses of the transformer's components. Those losses comprise the primary circuit's resistance (known either as the "copper losses" or as the "resistance losses") and the transformer's magnetic reluctance (known either as the "iron losses" or as the "magnetic losses").Reluctance is the techical description given to the energy necessary to excite the magnetic circuit and overcome its hysteresis, the effects of eddy currents, etc.For more information see the Related link shown below.