To answer this question a voltage must be given. Watts = Amps x Volts. <<>> Answer At 115 volts ac, 30 amps equals 3,450 watts.
A 15 amp circuit at 120 volts can safely power up to 1800 watts (15 amps x 120 volts = 1800 watts), but it is recommended to only draw 80% of the circuit's maximum capacity for safety reasons. So, in practice, it is best to limit the load to around 1440 watts on a 15 amp 120 volt circuit.
20 Amp * 120 Volts = 2400 Watts 2400 Watt * 80% max use = 1920 Watts planned normal usage for a circuit with a 20 Amp breaker.
Watts equals volts multiplied by amps. This would therefore be a five amp circuit.
Watts= voltage times amps. So if you divide Watts by voltage, you will get amps = .33333 or about a 1/3 amp load. This is assuming a 120 volt circuit.
A 20 amp circuit breaker at 208 volts can handle up to 4160 watts (20 amps x 208 volts = 4160 watts). This is calculated by multiplying the amperage by the voltage to determine the maximum wattage capacity of the circuit.
2400 watts.
A 20 amp breaker can handle up to 2400 watts per hour (20 amps x 120 volts = 2400 watts).
A 15a circuit can supply approximately 1650 watts, so 1650/65=25. I would stop at 20.
The electrical code states that circuit conductors that are fed by this breaker on a continuous load can only be loaded to 80%. Therefore you can have a load of 1,920 watts on this circuit. Assuming you install 8 watt bulbs you can have 240 on this circuit.
Any appliances that draw over 1500 watts should be on a 20 amp circuit.
The power flowing through the circuit can be calculated using the formula P = I * V, where P is power, I is current, and V is voltage. In this case, P = 1 amp * 120 volts = 120 watts. Therefore, 120 watts of power flows through the circuit.