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AMAX Inc pension plan?
i worked for Amax Chemical in Plant City,FL for 10 yrs, how can i find out who to contact about retirement information?
When was AMAX created?
AMAX was created in 1993.
When was AMAX Information Technologies created?
AMAX Information Technologies was created in 1979.
Does Amax of bromophenol blue vary with concentration?
Yes, the absorbance maximum (Amax) of bromophenol blue does vary with concentration. As the concentration of bromophenol blue increases, the Amax shifts from its initial value. This change in Amax can be used to determine the concentration of bromophenol blue in a solution through spectrophotometric analysis.
What is the NYSE ticker symbol for Cyprus Amax which was previously Phelps Dodge?
Phelps Dodge Corp. (NYSE:PD) completed its acquisition of Cyprus Amax Minerals Co. (NYSE: CYM) following a Dec. 2, 1999 meeting in Phoenix for Cyprus Amax shareholders. Cyprus Amax shares ceased trading on the New York Stock Exchange effective at the market's close. The combined company will retain the Phelps Dodge Corp. name and will trade on the New York Stock Exchange under the symbol PD.
What happened to Cyprus Amax Minerals Company stock?
I need to know if the 151 shares of Cyprus Amax Minerals Stock I have has any value? Thank You. Sarah Thompson
What major mergers took place in the copper industry in 1999?
In the end, two mergers were inked: Phelps/Dodge with Cyprus Amax, and Asarco with Grupo Mexico.
What has the author Donald R Guthrie written?
Donald R. Guthrie has written: 'Bioaccumulation from Amax/Kitsault of tailings' -- subject(s): Environmental aspects, Environmental aspects of Metals, Environmental aspects of Tailings (Metallurgy), Marine animals, Marine pollution, Metals, Metals in the body, Physiology, Tailings (Metallurgy), Trace elements in the body
Who offers free auto insurance quotes?
All Insurance companies will give you a free insurance quote. If an insurance comany wants to charge you a fee for a quote, run away as quicj as you can. State Farm, Farmers, Geico, Insurance Plus, Progressive, Amax, Farmers Insurance. Any company you can think of will give you a quote for free. Most companies now will also have teh ability for your to get a free quote at their company web site.
If I am given a circuit made of a diode a surge resistor and a DC source with which you can easily reverse the polarities what instruments do I need to know if the diode operates properly or not?
Any of these: Voltmeter: Across the Resistor, Vmax when diode conducts, 0 when you switch polarity Across the diode Vmin when conducting, Vmax when not. Ammeter: in series with ckt, Amax when conducting Amin when not, etc. Ohmmeter: No power required. Lo R one way, Hi R when leads reversed
Write a algorithm in c to add two sparse matrices?
#include <stdio.h> #include <conio.h> #include <alloc.h> #define MAX1 3 #define MAX2 3 #define MAXSIZE 9 #define BIGNUM 100 struct sparse { int *sp ; int row ; int *result ; } ; void initsparse ( struct sparse * ) ; void create_array ( struct sparse * ) ; int count ( struct sparse ) ; void display ( struct sparse ) ; void create_tuple ( struct sparse *, struct sparse ) ; void display_tuple ( struct sparse ) ; void addmat ( struct sparse *, struct sparse, struct sparse ) ; void display_result ( struct sparse ) ; void delsparse ( struct sparse * ) ; void main( ) { struct sparse s[5] ; int i ; clrscr( ) ; for ( i = 0 ; i <= 4 ; i++ ) initsparse ( &s[i] ) ; create_array ( &s[0] ) ; create_tuple ( &s[1], s[0] ) ; display_tuple ( s[1] ) ; create_array ( &s[2] ) ; create_tuple ( &s[3], s[2] ) ; display_tuple ( s[3] ) ; addmat ( &s[4], s[1], s[3] ) ; printf ( "\nResult of addition of two matrices: " ) ; display_result ( s[4] ) ; for ( i = 0 ; i <= 4 ; i++ ) delsparse ( &s[i] ) ; getch( ) ; } /* initialises structure elements */ void initsparse ( struct sparse *p ) { p -> sp = NULL ; p -> result = NULL ; } /* dynamically creates the matrix */ void create_array ( struct sparse *p ) { int n, i ; /* allocate memory */ p -> sp = ( int * ) malloc ( MAX1 * MAX2 * sizeof ( int ) ) ; /* add elements to the array */ for ( i = 0 ; i < MAX1 * MAX2 ; i++ ) { printf ( "Enter element no. %d:", i ) ; scanf ( "%d", &n ) ; * ( p -> sp + i ) = n ; } } /* displays the contents of the matrix */ void display ( struct sparse s ) { int i ; /* traverses the entire matrix */ for ( i = 0 ; i < MAX1 * MAX2 ; i++ ) { /* positions the cursor to the new line for every new row */ if ( i % MAX2 0 ) printf ( "\n" ) ; printf ( "%d\t", * ( s.result + i ) ) ; } } /* deallocates memory */ void delsparse ( struct sparse *p ) { if ( p -> sp != NULL ) free ( p -> sp ) ; if ( p -> result != NULL ) free ( p -> result ) ; }
What should be the spring constant k of a spring designed to bring a 1200 kg car to rest from a speed of kmh so that the occupants undergo a maximum acceleration of 5.0 g?
Talking about abstract models: springs don't really do that, you would need a damper. Spring (ideal one) would gradually slow the car and then repel it in opposite direction with the exact same velocity and the acceleration/deceleration would be greatest when the car comes to temporary rest. Of course there's no ideal spring and real spring has also properties of damper, but then it cannot be easily described using single abstract value of k. Also, when modeling crash event, you have to consider the length of deceleration. No damper or spring will save you, when there's no room for deceleration and you have to calculate it. Let's consider an ideal spring model: For deceleration to complete(in this case, car gets to momentary rest and then is repelled in opposite direction immediately), car has to transfer all of its kinetic energy(here the maximum) Ek = mvstart2 / 2 to the spring. Spring's maximum potential energy is: Ep = kx2 / 2, where x is maximum distance from spring's equilibrium. We can see that mv2 = kx2, so mv2 / x = kx. We also have to take into account the maximum deceleration/acceleration: mamax <= kx, which we can simplify to only the border case, where: mamax = kx. Comparing both equations: mamax = mv2 / x, so x = v2 / amax So, we've established our minimum spring length. We can put it into second equation, like: mamax = kv2 / amax, so we get k = mamax2 / v2, which is our k. Since you neglected to provide velocity, the best number for k is therefore (1/v2)*2.9X106 kg*m2/s4
