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How many host can you have for 10.20.50.0 subnet mask 255.255.255.0?
253. Valid addresses would be from 10.20.50.1 to 10.20.50.254 10.20.50.0 is the network address. 10.20.50.255 is the network broadcast address. Any network with a subnet mask of 255.255.255.0 will support 253 hosts.
What subnet mask would be used with the hosts in the 128 107 176 0 22 network?
255.255.252.0 22 Network Bits = 2 full octets (255.255) + 6 bits (252)
Explain how IPv6 would remove the requirement of subneting?
It would not. If the network is too big, you have to subnet it, for purposes of administration and efficiency. IP version 6 would not change this situation.It would not. If the network is too big, you have to subnet it, for purposes of administration and efficiency. IP version 6 would not change this situation.It would not. If the network is too big, you have to subnet it, for purposes of administration and efficiency. IP version 6 would not change this situation.It would not. If the network is too big, you have to subnet it, for purposes of administration and efficiency. IP version 6 would not change this situation.
What is the maximum number of bits that can be borrowed to create a subnet for a Class C network?
You can borrow 6 bits. Which would create a 255.255.255.252 subnet mask, but this subnet only contains 2 usable IP addresses. 7 bits would be 255.255.255.254, but that subnet is too small to have any use in the real world.
How many bytes in an IPX network address?
10 bytes - 4 for the network, 6 for the MAC address.
What IP addresses are subnetted A 139.233.12.12 255.255.255.0 B 10.0.0.1 255.255.255.0 C 192.168.0.1 255.255.255.0 D 190.233.17.3 255.255.255.0?
A, B and D are subnets. C is not. IP addresses A and D are both Class B subnets. Class B addresses normally have a subnet mask of 255.255.0.0. The first two bits of a class B network are always 10 which leaves 14 bits for the network prefix, thus allowing up to 16,384 separate Class B networks (including 139.233.0.0 and 190.233.0.0). The last 16 bits denote the host number thus there can be up to 65,536 hosts per network. By specifying a subnet mask of 255.255.255.0 the network can be divided into as many as 256 separate subnets each with 256 hosts. IP address B is a Class A subnet. Class A addresses normally have a subnet mask of 255.0.0.0. The first bit of a class A network is always 0, which leaves 7 bits for the network prefix, thus allowing up to 127 Class A networks (including 10.0.0.0). The last 24 bits denote the host number thus there can be up to 16,777,216 hosts per network. By specifying a subnet mask of 255.255.255.0, the hosts can be divided into as many as 65,536 separate subnets each with up to 256 hosts. IP address C is a Class C address, but is not a subnet. Class C addresses normally have a subnet mask of 255.255.255.0. The first three bits in a Class C network are always 110, leaving 21 bits for the network prefix, thus allowing up to 2,097,152 Class C networks (including 192.168.0.0). The last 8 bits denote the host number thus there can be up 256 hosts per network. To make a subnet out of a Class C address you must have a subnet mask of 255.255.255.X, where X may be 192, 224, 240, 248 or 252. That is, 2, 3, 4, 5 or 6 bits to denote the subnet and the remaining bits to denote the hosts. Thus a subnet mask of 255.255.255.192 would allow as many as 4 subnets each with up to 64 hosts, while a subnet mask of 255.255.255.240 would allow as many as 16 subnets each with up to 16 hosts. It should be noted that the maximum number of hosts is actually 2 less than the figures shown above. This is because the host address with all 0 bits is reserved for network address while the host address with all 1 bits is reserved for broadcasting.
How is the network address found from a listed IP address?
It is basically very easy depending on the class. When you start to figure in subnet masking, things get complicating. I'll start with the simple bit. I'm assuming you are questioning for IPv4. Say you have a computer with the IP address 10.14.10.88, with a subnet mask of 255.0.0.0. This means that you keep the numbers that correspond to the 255 and replace the other numbers with 0. So the network address of the network this computer is connected to is 10.0.0.0. Another example would be if you are given an IP of 172.155.8.101/16. The /16 is the subnet mask. It means you keep the first 16 bits and drop the rest to determine the network address. So the Net Address is 172.155.0.0. In an IPv4 address, every number number between a dot is 8 bits. So if the IP address was instead 172.155.8.101/24, then the net address would be 172.155.8.0. But what if the subnet mask isn't 255 or divisible by 8, depending on which method is being used? Say now we have a computer on the network 148.76.55.189/27 and we want to find the net address on that. Well the first three are easy 148.76.55.x, but now what? Let's convert both the subnet mask and the ip address into binary. The subnet mask is 27 ones, followed by 5 zeros. Remember, IPv4 is made up of four parts, each part being 8 bits, and the 27 means you need to keep the first 27 bits. So our subnet mask is 11111111.11111111.11111111.11100000 Next, we need to convert the ip address we were given to binary. It would probably help if you used an online tool for this if you are not familiar with binary. Our ip address comes out to be 10010100.01001100.00110111.10111101 Now, much like before, we keep the amount of bits specified by the subnet mask, then turn the rest to zeros. So we have a network address of 10010100.01001100.00110111.10100000 If we convert this back to decimal, then we learn that the final number is not zero like before, but is in fact, 160. So the network address for 148.76.55.189/27 is 148.76.55.160. It can take some practice with subnet masks that aren't full bytes, but eventually you will get the hang of it. I will add a nice binary x decimal conversion tool to the related links. Just remember when you convert using the tool, make sure that if it doesn't turn out to be 8 bits, add zeros to the beginning of the number to make it 8 bits. For example, the tool converted 55 to 110111, which is only 6 bits. So I add two zeros to the beginning of it to make is 8 bits, 00110111. It's no different than adding zeros to a decimal number like 19. 19 and 00019 are the same. See what I mean?
Suppose an isp has class c address ie 193.5.48.0 if the isp has three customers with only six computers each then what ip addresses are assigned to three customers by using classless addressing?
: The ISP can assign the smallest subnets to each customer, i.e., he can use subnet mask 255.255.255.248. Note: 24810= 111110002 In this way, he can assign 8 IP addresses for each customer For example, ISP assigns 193.5.48.8 to 193.5.48.15 to one customer, since 810 = 000010002, 1510 = 000011112, these IP addresses are in the same subnet using subnet mask 255.255.255.248. The customer will use 193.5.48.8 as his subnet ID and 193.5.48.15 as the local broadcasting address. He has 6 IP addresses for computers.
The two parts of MAC addresses?
Yes - the first bits specify the network, the remaining bits, a host within a network. There is no fixed number of bits for the network; this may vary.Yes - the first bits specify the network, the remaining bits, a host within a network. There is no fixed number of bits for the network; this may vary.Yes - the first bits specify the network, the remaining bits, a host within a network. There is no fixed number of bits for the network; this may vary.Yes - the first bits specify the network, the remaining bits, a host within a network. There is no fixed number of bits for the network; this may vary.
What is similar about MAC address in different computers?
IP addresses are unique on a given network. Networks are divided into subnets. A Subnet is specified by the network mask. If you look at an ip address and network mask in binary (as machines do) it all makes more sense. A common network mask you will see in a private ip network is (in binary) 11111111 11111111 11111111 00000000 grouped 8 bits at a time for clarity That is 255.255.255.0 look familiar? The mask tells us that any address that is to be considered part of our network must match exactly wherever there is a binary 1 and can differ anywhere there is a binary 0. Thus the addresses: 11000000 10101000 00000000 00000001 (192.168.0.1) 11000000 10101000 00000000 00000010 (192.168.0.2) 11000000 10101000 00000000 00000011 (192.168.0.3) are the same when we look in the columns that have binary 1 in the mask (ie the first 3 decimal numbers) and differ only in the columns where there is a binary 0. An address like 11000000 10101000 00000001 00000010 (192.168.1.2) differs in a column where there is a binary 1, so this address is not in our subnet. Thus, to actually answer the question, the parts of the address that are the same in different computers (if they are on the same subnet) is determined by the network mask.
How many Subnets can you create on a Class C address with the subnet mask being 255.255.255.192 the answer i got was wrong and I don't understand where I went wrong please help. Thank you?
192 is equal to 2 bits borrowed 2^2 = 4 the number of subnets and host are 64 because 2 bits borrowed from the 8 bits of a class C network is 6, therfore 2^6 = 64.
Define and describe the two parts of a mac address?
The first 6 digits is the OUI(Organizationally Unique Identifiers given by vendors and then the last 6 digits are used to represent the NIC uniquely with the OUI value.
