The largest integer remainder is 6.
Assuming the number holds an unsigned number, the range of numbers for 4 bits is 0-7. 7 is a prime number.
-52x <= 7 (-52x)/(-52) >= 7/(-52) {divide both sides by -52, and reverse the inequality when dividing by a negative. x >= -7/52 There is no largest integer value for x. If the question was ... greater than or equal to ... then the solution would be x <= -7/52, and the largest integer value would be -1.
Because the next larger integer is 1000000 which has 7 digits.
By the uniqueness of numbers, the only integer that represents -7 is -7.
Yes, 7 is a positive integer.
A nibble is 4 bits, so the largest unsigned number is 1111, or 15. Also, the largest signed number is 0111, or 7.
The integer "-8" is less than "-7".
log2 200 = ln 200 ÷ ln 2 = 7.6... → need 8 bits. If a signed number is being stored, then 9 bits would be needed as one would be needed to indicate the sign of the number.
No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106
7.09 rounded to the nearest integer is 7.
Because 7 is the largest positive integer that divides evenly into all of those numbers with no remainder.