What z value corresponds to 17 percent of the data between the mean and the z value?
I believe your question is to find a range going from the mean
to a z-value on the standard normal distribution that corresponds
to 17% of the area. A normal distribution goes from values of minus
infinity to positive infinity. A standard normal distribution has a
mean of 0 and an standard deviation of 1. It is usually best if you
draw a diagram, in this case a bell shape curve with mean = 0. The
area to the left of the mean is 50% of the total area. We find a z
value that corresponds to 67% (50% + 17%) of the area to the left
of this value. This can be done either with a lookup table or a
spreadsheet program. I prefer excel, +norminv(0.67) = 0.44. The
problem could also be worded to find the area going from a z-value
to the mean. In this case, we must find a z-value that corrsponds
to 33% (50-17). Using Excel, I calculate +norminv(0.33) =
-0.44.