One-fifth of the tank
The atoms in O2 move much too quickly to boil. ;D
a.O2 b. O2+ C. O2- d. O22-
13 quarts supposedly but I can usually only get 12 in my 1948 model D
I tAnk d Must pUpuler spuRt iN d wUrld Is eug toOs tAnk u.
Do you mean a cylindrical tank? Which is the diameter of the base, which is the height? if d = 48 and h = 20, then r = 24. V = pi r2 h = 3.14 x (24)2 x 20 = 36172.8 cubic inches for gallons divide by 231 ... v = 156.6 gallons
"Twinkle, Twinkle Little Star" C C G G / A A G (hold) / F F E E / D D C (hold) / G G F F / E E D (hold) / G G F F / E E D (hold) / C C G G / A A G (hold) / F F E E / D D C (hold).
The d orbitals in a sublevel can hold a maximum of 10 electrons.
Bb Bb F F G G F (hold for 2 beats) Eb Eb D D C C Bb (hold for 2 beats) F F Eb Eb D D C (hold for 2 beats) F F Eb Eb D D C (hold for 2 beats) Bb Bb F F G G F (hold for 2 beats) Eb Eb D D C C Bb (hold for 2 beats)
The second energy level can hold a maximum of 10 d electrons. Each d subshell can hold a maximum of 5 electrons.
A#D Cadd9 D#A
You need to balance your equation. (a)CHCH + (b)O2 --> (c)H2O + (d)CO2 First look at the water... it takes 2xH (which is in 1 acetylene molecule) & 1/2 (O2) molecule. (changed to b' for partially calculated oxygens). (1)CHCH + (b')O2 + (1/2) O2 --> (1)H2O + (d)CO2 Now, since each carbon in carbon dioxide needs 2 oxygens... and you started with 2 carbon atoms... d=2, and also b' = 2 (1)CHCH + (2)O2 + (1/2) O2 --> (1)H2O + (2)CO2 Simplify: CHCH + (2.5)O2 --> H2O + 2CO2 And you end up needing 2.5L of O2 for every liter of Acetylene.