0
None, since there can be no conversion.
A metre is a measure of length in 1-dimensional space while a millilitre is a measure of volume in 3-dimensional space. The two measure different characteristics and, according to the most basic principles of dimensional analysis, any attempt at comparisons or conversions between the two are fundamentally flawed.
What else can I help you with?
You want to make a 275.0 mL of a 0.15 M solution of HCl. How many mL of a 6.0 M solution do you need?
To calculate the volume of the 6.0 M HCl solution needed, you can use the formula M1V1 = M2V2. Plugging in the values, you get: (6.0 M)(V1) = (0.15 M)(275.0 mL). Solving for V1, you will need 5.7 mL of the 6.0 M HCl solution to make 275.0 mL of a 0.15 M solution.
How many ml of 110 M of HCl are needed to completely neutralize 54ml of 106 M of BaOH2 solution?
A concentration of 110 M or 106 M doesn't exist.
How many ml of 0.4040 m HNO3 would be needed to nuetralize 55.00 ml of 0.124m potassium hydroxide?
The answer is 16,9 mL.
How many grams of lidocaine are in 150 ml of a 2.5 M solution?
150 mL of a 2.5 M lidocaine solution contain 87,9 g.
How do you make 25 ml of a 0.0010 M HCl starting with 0.010 M HCl?
To make 25 ml of 0.0010 M HCl from 0.010 M HCl: (0.010 M) x V1 = (0.0010 M) x 25 ml V1 = (0.0010 M * 25 ml) / 0.010 M V1 = 2.5 ml of the 0.010 M HCl solution should be diluted to 25 ml to get 0.0010 M HCl.
How many moles of bromine are in 24.5 mL of 1.0 M bromine in CH2Cl2?
24.5 mL of a solution 1.0 M bromine contain 0,0245 moles.
Calculate the final concentration (in Molarity) when 25 mL of water is added to 95 mL of 1.4 M LiCl.?
25 ml added to 95 ml give a final volume of 120 ml (95 ml)(1.4 M) = (120 ml)(x M) x = 1.1 M
What volume of 3.0 M HCl sould be obtained to prepare 100 mL of 1.0 M HCL?
To prepare 100 mL of 1.0 M HCl from a 3.0 M stock solution, you can use the formula: (M_1V_1 = M_2V_2). Solving for V1: (3.0 M)(V1 mL) = (1.0 M)(100 mL), thus V1 = 33.3 mL. So, you would need to measure out 33.3 mL of the 3.0 M HCl solution and then dilute it to 100 mL to obtain 1.0 M HCl.
How many mL of a 0.400 M concentrated solution must be added to water to get a more dilute solution with a total volume of 10.0 mL and a new concentration of 0.160 M?
To find the volume of 0.400 M solution to add, you can use the dilution formula C1V1 = C2V2: (0.400 M)(V1) = (0.160 M)(10.0 mL) V1 = (0.160 M)(10.0 mL) / 0.400 M V1 = 4.0 mL Therefore, 4.0 mL of the 0.400 M solution should be added to water to achieve a total volume of 10.0 mL with a concentration of 0.160 M.
What is the HCl concentration if 53.1 mL of 0.300 M NaOH is required to titrate a 15.0 mL sample of the acid?
HCl + NaOH ---> NaCl + H2O(53.1 ml)(0.300 M) = (15.0 ml)(x M)x = 1.06 M
How many ml of 6.00m hcl are needed to prepare 1000 ml of a 100m hcl?
100 M HCl don't exist.
What volume of a 012 M KOH solution is needed to react with 23 mL of 0.22 M HCl?
To find the volume of KOH solution needed, use the equation: M1V1 = M2V2 where M1 = 0.22 M, V1 = 23 mL, M2 = 0.12 M, and V2 is the volume of KOH solution needed. Rearranging the equation gives: V2 = (M1 × V1) / M2 = (0.22 M × 23 mL) / 0.12 M = 42.33 mL Therefore, 42.33 mL of the 0.12 M KOH solution is needed to react with 23 mL of 0.22 M HCl.
