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Q: How many liters of pure acid are there in 8 liters of a 20 percent solution?
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How many liters of a 20 percent solution of acid should be added to 10 liters of a 30 percent solution of acid to obtain a 25 percent solution?

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How many liters of a 90 percent acid solution must be mixed with a 15 percent acid solution to get 600 L of a 80 percent solution?

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Let x be the liters of the 30% acid solution and y be the liters of the 60% acid solution. We can set up a system of equations: x + y = 50 (total liters) and 0.3x + 0.6y = 0.57*50 (acid content). Solving this system of equations, we find that x = 20 liters of the 30% acid solution and y = 30 liters of the 60% acid solution.


How many liters of 10 percent alcohol solution must be mixed with 70 liters of a 70 percent solution to get a 30 percent solution?

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How many liters of hydrochloric acid are contained in 300 liter of a solution that is 10 hydrochloric acid by volume'?

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How many liters of water must be added to 7 liters of a 20 percent acid solution to obtain a 10 percent acid solution?

7 liters of a 20% acid solution consists of 1.4 liters of acid (20% of the total volume) mixed with 5.6 liters of water (80% of the total volume). The amount of acid isn't going to change in the new solution. You are just going to add enough water to make it a 10% solution instead of a 20% solution. So it will be more dilute. That means that 1.4 liters of acid will represent 1/10 of the volume of the new solution. So the total volume of the new solution will be 10 x 1.4 or 14 liters. The amount of water in the new solution will be 14 - 1.4 = 12.6 liters. That is a difference of 12.6 - 5.6 = 7 liters from the amount of water you started with. So you need to add 7 liters of water to the original 20% solution to make it a 10% solution. This makes sense because if you double the amount of the mixture from 7 liters to 14 liters and the amount of acid is unchanged, the solution will be half as strong.


How many liters of 9 percent salt solution and 18 percent salt solution are needed to make 18 liters of 10 percent salt solution?

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Let x = the amount of 20% solution Let x + 10 = the amount of the final solution. So we have: (.20)x + (.50)(10) = (.40)(x + 10) .20x + 5 = .40x + 4 .20x = 1 x = 5 liters of 20% solution of saline.


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