Gun powder is typically measured by weight, using the grain as a unit of measure. There are about 15 grains to one gram.
There are 7,000 grains in one pound of gun powder. Grains are measured at 437.5 grains per ounce.
7000 grains of powder, lead, or peanut butter to one pound.
Depends on the bullet weight AND the type of powder used.
As used here, grain is a measure of weight- ABOUT 1 gram. Smokeless gun powder is usually grey to dark grey, and may consist of tiny flakes, disks or rods.
A grain is a weight. Smaller than an ounce or a gram- its a tiny amount. When talking about guns, grains refers to how much gunpowder is in each bullet. A bullet with more grains of gunpowder has more bang to it than a bullet with less grains of gun powder.
What size shell in legnth are you asking about?
A typical 9mm round contains around 5-7 grains of powder. The exact amount can vary depending on the specific type of ammunition and powder load used.
Depends on which powder is used, and there are several. If using Winchester W748, it would be about 23.5 grains of weight of powder.
7.0 grams cost $300; divide 300 by 7 to find cost per gram: 300 ÷ 7 = $42.86 per gram.
With ammunition, the term GRAIN is a measure of weight- there are 7000 grains to a US pound. It does not refer to the number of individual flakes of powder (grains). Load data will vary depending on the weight of shot to be fired, and how hard you want that to shoot- and it also varies depending on which of several powders you use. For example, a 1 oz shot load might use from 20-25 grains of powder X, 22-27 grains of powder Y- and a 1 1/8th oz shot load might use 18-14 grains of X, etc.
I would need to know the caliber and type (revolver, single shot. flintlock, percussion) to answer the question exactly, but the best place to start is with as many grains of powder as the caliber divided by half for a hand gun or revolver as a MAXIMUM LOAD. So a .45 cal. would be about 20-23 grain. I usually start out around 12-15 grains and work from there.