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How many bits would you borrow to subnet 172.16.100.0 to have at least 500 hosts?
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∙ 11y ago
we need to borrow 7 bits to subnet 172.16.100.0 to have at least 500 hosts and the subnet mask will be 255.255.254.0
Wiki User
∙ 11y ago
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In a class A how many subnet bits are needed to make at least 365 useable hosts or subnets?
You would need at least 9 bits to borrow. Since 8 bits gives only 255 the additional bit will get you 256. Adding 256 + 128 gives you at least 384 subnets or hosts.
How many would you borrow to subnet 192.168.50.0 down to at least 10 networks?
4 bits
If you have the following Network ID 131.112.0.0 You need at least 500 hosts per network How many networks can you create What subnet mask will you use?
If you need to divide it up into the maximum number of subnets containing at least 500 hosts each, you should use a /23 subnet mask. This will provide you with 128 networks of 510 hosts each. If you used a /24 mask, you would be limited to 254 hosts. Similarly, a /22 mask would be wasteful, allowing you 1022 hosts.
As network administrator what is the subnet mask that allows 510 hosts given the IP address?
N - network bitsH - host bitsIf you are following the first octet rule, this is a class B network with a subnet mask of 255.255.0.0 (N.N.H.H). We can subnet this by "borrowing" some bits from the host portion. There are 16 network bits and 16 host bits. There is a simple formula to calculate the proper subnet mask.2 to the power of what equals at least 510(2^X)? We have a total of 16 host bits to borrow from. 2^1...2^2...2^3...Etc2^9= 512 - 2 = 510 host addressesWe subtract two because the network and broadcast address are not usable addresses. As we can see we need at least 9 host bits to get 510 hosts per subnet.Take 32 and subtract it from the host bits you need. So 32-9=23. Your subnet mask now has 23 network bits instead of 16.In binary the original subnet mask would be 11111111.11111111.00000000.00000000.In binary the new subnet mask is 11111111.11111111.11111110.00000000.If you convert this into dotted decimal form you get 255.255.254.0.TLDR: 172.30.0.0 - 172.30.1.255255.255.254.0
Subnet 192.168.1.0 to three departments each having at least ten computers?
If you go with a subnet of 182.168.1.0/255.255.255.0 you can support up to 254 IP addresses. So 30 PCs would not be an issue,
Ate these two computers on the same network IP192.167.222.4 Subnet255.255.555.0 Gateway192.168.222.1 and IP192.168.222.6 Subnet255.255.0.0 Gateway192.167.222.1?
For a start, two computers on the same network should have the same subnet mask. If two computers that are indeed on the same network have different subnet masks, there is a design problem. Now, even if you look only at the last subnet mask - the least restrictive one - the computers are NOT on the same subnet mask. The subnet mask 255.255.0.0 indicates that the first two bytes (or the first 16 bits) of an IP address have to match, to be considered part of the same network. If you look at the IP addresses, this is not the case.
What is the second subnet of 172.16.0.0?
172.16.0.0/16 gives you 65534 possible hosts within 1 subnet. By binary math, you would need to increase the subnet mask to divide the network into subnets. Think of the additional subnet mask bits as a binary value. With 0 extra bits in the masks, you have 1 subnet. With 1 bit, you have 2. With 2 bits, you have 4. With 3 bits, you have 8. With 4 bits, you have 16. We need 8, so we should add 3 bits to the subnet mask. This would be a base CIDR of 172.16.0.0/19. Since there are 256 possibilities in the 3rd octet (Based on Class B network), divide by 8. The resultant number is the increment value for each network address. 256 / 8 = 32. Therefore, your networks would be: 172.16.0.0/19 172.16.32.0/19 172.16.64.0/19 172.16.96.0/19 172.16.128.0/19 172.16.160.0/19 172.16.192.0/19 172.16.224.0/19 With maximum (65536 / 8 - 2) 8190 hosts per subnet. Additional: Since we have 19 network bits, there are 13 bits remaining for hosts (total, as always 32). An all 0 string of host bits would leave you with your base network number ex> 172.16.0.0/19 , host with all 0's 10101100.00010000.00000000.00000000 The resultant would be 172.16.0.0, which is your network address. Conversely, having a host with all 1's: 10101100.00010000.00011111.11111111 This would result in 172.16.31.255, which is the broadcast address for the first subnet. These aren't usable as assignable addresses, but are used for network and broadcast purposes. Using all of the 3 borrowed bits in a 111 situation gives you a resultant of 172.16.224.0/19, which is a legitimate network address. Network bits in this case carry over from the /16, and are simply added on. An IP address of 172.16.255.255 would be the broadcast address for the final subnet. ex> 10101100.00010000.11111111.11111111 If you were doing a class A network, this wouldn't be as applicable. If all 3 of the first bits of a network address are 1, this puts your IP into a class D (224.0.0.0/4) subnet which is reserved for multicasting. This is only applicable to the first bits of the network address (starting from the very beginning). Hope this helped at least a little.
3 If you have been called in to design a network for your company What if your company subscribes to a class B IP addressing You are required to subnet the network in your design such that at least 10?
i dnt know
Why each computer have its own IP addresses and sub net work?
Computers have a unique IP address to identify them, just like in the real world having 2 equal addresses causes confusion.They don't have their own subnet though, they are part of a subnet which consists of at least 2 pc's. Subnets each have their own broadcast address and default gateway, as well as a limited amount of IP-addresses (determined by the subnet mask) to prevent abuse and to ease scaling.
How tocalculate subnet mask address?
Calculating a subnet mask depends on whether you are using the default, classful mask or a true subnet mask to divide a network into smaller pieces.The defaults are on octet boundaries (every 8 bits):255.0.0.0 class A network255.255.0.0 class B network255.255.255.0 class C networkAny other type of subnet mask with 4 octets (iPV4) can use combinations of those with any octet value from 0 - 255. No number may be larger than 255.Calculating other subnet masks would be based on how many subnets you want in the network. You could have values such as:255.192.0.0255.255.248.0.0255.255.255.252The first octet must at least be 255. The other octets may change, based on whether it is a classful default network or it is being subnetted.
How do you calculate a subnet mask address of networking?
Calculating a subnet mask depends on whether you are using the default, classful mask or a true subnet mask to divide a network into smaller pieces.The defaults are on octet boundaries (every 8 bits):255.0.0.0 class A network255.255.0.0 class B network255.255.255.0 class C networkAny other type of subnet mask with 4 octets (iPV4) can use combinations of those with any octet value from 0 - 255. No number may be larger than 255.Calculating other subnet masks would be based on how many subnets you want in the network. You could have values such as:255.192.0.0255.255.248.0.0255.255.255.252The first octet must at least be 255. The other octets may change, based on whether it is a classful default network or it is being subnetted.
How do you calculate a subnet mask address in networking?
Calculating a subnet mask depends on whether you are using the default, classful mask or a true subnet mask to divide a network into smaller pieces.The defaults are on octet boundaries (every 8 bits):255.0.0.0 class A network255.255.0.0 class B network255.255.255.0 class C networkAny other type of subnet mask with 4 octets (iPV4) can use combinations of those with any octet value from 0 - 255. No number may be larger than 255.Calculating other subnet masks would be based on how many subnets you want in the network. You could have values such as:255.192.0.0255.255.248.0.0255.255.255.252The first octet must at least be 255. The other octets may change, based on whether it is a classful default network or it is being subnetted.
