How to solve Log 2 Log 2 Log 2 X equals 0 here 2 is the base not any number?
I guess you mean log2{log2[log2(x)]} = 0 ?Let Y = {log2[log2(x)]}, so you have log2[Y] = 0The solution to this is Y = 1,Then you a simpler equation: log2[log2(x)] = 1Let Z = log2(x), so log2[Z] = 1, solves to Z = 2,so log2(x) = 2, and x = 4