Both of them are just updates for window xp. Window xp needs updates because it's crap. Sp3 is a better update for window xp and it is the most current one. You probably need it for iTunes or other modern applications.
sp3 is better
SP3 has new updates already installed than SP2
Service Pack 3 or (SP3) has more enhanced component compared to Service Pack 2 (SP2). Comments? Email at angelo.ment@gmail.com
A C-C sigma bond formed by sp2-sp2 overlap is stronger than one formed by sp3-sp3 overlap because the sp2 hybrid orbitals have a greater s-character (33%) compared to sp3 orbitals (25%), leading to more effective overlap and stronger bonding. This higher s-character causes the sp2-sp2 bond to be shorter and stronger than the sp3-sp3 bond.
In an sp hybridization, the sp3 orbitals are arranged at angles of 180 degrees from each other, resulting in a linear configuration. The sp3 orbitals are not separate entities, but they form a single hybrid orbital.
Depends. Windows requires that you have SP1 installed and recommends you have SP2 installed, but SP2 it is not necessary, in order to install SP3. So if you have just SP1 installed you are going to get SP2 and all subsequent updates along with SP3. If you have SP2 installed the SP3 update is around 16.1 MB. If you have only SP1 installed the download will be as much as 57.5 MB. It all depends on what you already have installed. I suggest you install SP2 before installing SP3. I also suggest you let Automatic Updates install this at a time when you are not on the computer. If you are on Dial-Up, order SP3 CD from Microsoft.
No.
sp3,sp2,sp, these are covalent
The C in h3c is sp3 hybridized The c in ch is sp2 hybridized the c in ch2 is sp2 hybridized
// sparse matrix addition.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include<stdio.h> #include<conio.h> void read_sp_matrix(int sp[100][100]); void add_sp_matrix( int sp1[100][100],int sp2[100][100],int sp3[100][100]); void print_sp_matrix(int sp[100][100]); int _tmain(int argc, _TCHAR* argv[]) { int sp1[100][100],sp2[100][100],sp3[100][100],sp[100][100],i,j,k,r,c; printf("Enter the first sparse matrix row size,column size & number of non zero elements"); read_sp_matrix(sp1); printf("Enter the second sparse matrix row size,column size & number of non zero elements"); read_sp_matrix(sp2); printf("You entired the first sparse matrix \n"); print_sp_matrix(sp1); printf("You entired the second sparse matrix \n"); print_sp_matrix(sp2); printf("Result of sparse matrix addition \n"); add_sp_matrix(sp1,sp2,sp3); print_sp_matrix(sp3); getch(); } void read_sp_matrix(int sp[100][100]) { int i,j,k,r,c,t; scanf("d%d",&sp[0][0],&sp[0][1],&sp[0][2]); r=sp[0][0]; c=sp[0][1]; k=1; printf("Enter the sparse matrix elements \n"); for(i = 0; i < r; i++) { for(j = 0; j < c; j++) { scanf("%d",&t); if(t != 0) { sp[k][0] = i; sp[k][1] = j; sp[k][2] = t; k++; } } } } void add_sp_matrix(int sp1[100][100],int sp2[100][100],int sp3[100][100]) { int i,j,k,t1,t2,x; t1 = sp1[0][2]; t2 = sp2[0][2]; i=j=k=1; if((sp1[0][0] !=sp2[0][0])&&(sp1[0][1] !=sp2[0][1])) { printf("Invalid matrix ,try to correct \n"); goto x; } while((i <= t1)&&(j <= t2)) { if(sp1[i][0] < sp2[j][0]) { sp3[k][0] = sp1[i][0]; sp3[k][1] = sp1[i][1]; sp3[k][2] = sp1[i][2]; k++; i++; } else if(sp1[i][0] > sp2[j][0]) { sp3[k][0] = sp2[j][0]; sp3[k][1] = sp2[j][1]; sp3[k][2] = sp2[j][2]; k++; j++; } if((sp1[i][0] sp2[0][1]) { s = sp1[i][2] + sp2[j][2]; if(s != 0) { sp3[k][0] = sp1[i][0]; sp3[k][1] = sp1[i][1]; sp3[k][2] = sp1[i][2] + sp2[j][2]; k++; i++; j++; x++; } else { i++; j++; } } else if(sp1[i][1] > sp2[j][1]) { sp3[k][0] = sp2[j][0]; sp3[k][1] = sp2[j][1]; sp3[k][2] = sp2[j][2]; k++; j++; x++; } else { sp3[k][0] = sp1[i][0]; sp3[k][1] = sp1[i][1]; sp3[k][2] = sp1[i][2]; k++; i++; x++; } } else if(sp1[i][0] > sp2[j][0]) { sp3[k][0] = sp2[j][0]; sp3[k][1] = sp2[j][1]; sp3[k][2] = sp2[j][2]; k++; j++; x++; } else { sp3[k][0] = sp1[j][0]; sp3[k][1] = sp1[j][1]; sp3[k][2] = sp1[i][2]; k++; i++; x++; } } while(i <= t1) { sp3[k][0] = sp1[i][0]; sp3[k][1] = sp1[i][1]; sp3[k][2] = sp1[i][2]; k++; i++; x++; } while(j <= t2) { sp3[k][0] = sp2[j][0]; sp3[k][1] = sp2[j][1]; sp3[k][2] = sp2[j][2]; k++; j++; x++; } sp3[0][0] = sp1[0][0]; sp3[0][1] = sp1[0][1]; sp3[0][2] = x/*sp1[0][2]*/; int d = k-1; printf("The Resultant Matrix \n"); for(i= 0;i<=d;i++) { for(j=0;j<3;j++) { printf("%2d ",sp3[i][j]); } printf("\n"); } getch(); }
Carbon rehybridizes from sp3 to sp2 in tin chemistry due to the formation of a coordinate covalent bond between carbon and tin. This leads to the promotion of one electron from a lone pair orbital on carbon to form a π bond with tin, requiring the carbon to undergo sp3 to sp2 hybridization to accommodate the new bonding situation.
The hybridization of SO32- is sp3. This is because sulfur has 1 lone pair and 3 bonding pairs, resulting in the promotion of one of its s orbitals to form 4 equivalent sp3 hybrid orbitals for bonding.