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A ball is thrown vertically upwards with velocity of 19.6ms what is the maximum height to which it will reach?
Wiki User
∙ 12y ago
apply the formula:
v2 - u2 = 2as.
Here v= 0; u = 19.6m/s; a = -g ,find s and that's max. heigth
Wiki User
∙ 12y ago
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A boy kicks a ball vertically upwards with an initial velocity of 12m/s. Calculate the time taken by the ball to reach the maximum hight and the maximum, height reached by the ball?
The time taken by the ball to reach the maximum height is 1 second. The maximum height reached by the ball is 36 meters.
What relationship exists between the initial velocity and the maximum height reached by an object thrown upward?
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
The velocity of a body thrown vertically upward is reduced into half in one secondwhat is the maximum height attained by it?
The maximum height attained by the body can be calculated using the formula: height = (initial velocity)^2 / (2 * acceleration due to gravity). Since the velocity is reduced to half in one second, we can calculate the initial velocity using the fact that the acceleration due to gravity is -9.81 m/s^2. Then, we can plug this initial velocity into the formula to find the maximum height reached.
An arrow is shot vertically upwards with an initial speed of 12 m s What is the maximum height the arrow can reach Take g 10 N kg?
The maximum height the arrow can reach can be calculated using the equation h = (v^2)/(2g), where v is the initial velocity (12 m/s) and g is the acceleration due to gravity (10 m/s^2). Plugging in the values, we get h = (12^2)/(2*10) = 7.2 m. Therefore, the maximum height the arrow can reach is 7.2 meters.
An object is thrown vertically upward when does it reach maximum height?
when the object reaches maximum height, the velocity of the object is 0 m/s.It reaches maximum height when the gravity of the body has slowed its velocity to 0 m/s. If there is no gravity and there is no external force acting on it then it will never reach a maximum height as there wont be a negativeaccelerationdemonstrated by newtons first law.Where there is and you have the objects initial velocity then you can use :v^2 = u^2+2.a.sv = Velocity when it reaches Max. height so v = 0u = Initial Velocity (m/s)a = Retardation/ Negative Acceleration due to gravity, -9.80m/s ^2And then the unknown (s) is the displacement, or height above ground, and if everything else is in the right format it should be in metres.
Where does a ball has the greatest potential energy?
A ball has the greatest potential energy at its highest point, such as when it is held at the top of a hill or at its maximum height when thrown vertically upwards. This is because the gravitational force acting on the ball is at its maximum, giving it the highest potential energy.
What is the Effect of changing the angle of projection on the magnitude of maximum height?
Max height H = u2 sin2@ / 2g So as we increase the angle of projection, then max height too increases and its value will be just u2/2g when it is projected vertically upwards ie @ = 90 deg
What is the equations of motion for an object thrown vertically upwards?
The equation of motion for an object thrown vertically upwards is given by: [ v_f = v_i - gt ] [ h_f = h_i + v_i t - \frac{1}{2}gt^2 ] Where: ( v_f ) is the final velocity, ( v_i ) is the initial velocity, ( h_f ) is the final height, ( h_i ) is the initial height, ( g ) is the acceleration due to gravity, and ( t ) is the time elapsed.
When bullet is fired upwards vertically it gains in?
When a bullet is fired upwards vertically, it gains potential energy as it moves against gravity. This increase in potential energy comes at the expense of its initial kinetic energy. Eventually, the bullet will reach its maximum height and then begin to fall back towards the ground, converting its potential energy back into kinetic energy.
A ball thrown vertically upward returns to the starting point in 8 seconds.find its initial velocity.?
The total time of flight for a ball thrown vertically upwards and returning to its starting point is twice the time taken to reach maximum height. Therefore, the time taken to reach maximum height is 4 seconds. Given that the acceleration due to gravity is -9.8 m/s^2, using the kinematic equation v = u + at, where v is the final velocity (0 m/s at maximum height), u is the initial velocity, a is the acceleration due to gravity, and t is the time, you can solve for the initial velocity. Substituting the values, u = 9.8 * 4 = 39.2 m/s. Therefore, the initial velocity of the ball thrown vertically upward is 39.2 m/s.
What is the boy throw a stone vertically upward with an initial velocity of 6.0 ms?
The boy throws a stone vertically upward with an initial velocity of 6.0 m/s, meaning the stone is moving against gravity. It will reach a maximum height and then fall back down due to gravity. The stone will eventually return to the ground after reaching its highest point.
How does angle of projection affect the maximum height?
The angle of projection affects the maximum height by determining the vertical and horizontal components of the initial velocity. At 90 degrees (vertical), all the initial velocity is vertical which results in maximum height. As the angle decreases from 90 degrees, the vertical component decreases, leading to a lower maximum height.
