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10.150.100.9627? This isn't a valid IP address .......
BUT, assuming you meant to say 10.150.100.96/27, then the subnetwork address is 10.150.100.96, the 1st host address is 10.150.100.97, and the broadcast address is 10.150.100.127.
The /27 means the 1st 27 bits are network, the remaining 5 are host addresses. The subnet address would be 255.255.255.224.
If someone could double check my math, it would be appreciated, as I am a newbie too.
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What is the effect of a router on delimiting broadcast traffic and conserving bandwidth?
Generally speaking, routers will unicast-forward incoming packets which have a network broadcast address as destination, unless they are directly connected to that network/subnet and therefore know that the destination address is a broadcast address
What is the broadcast address of network 192.168.113.216.255.255.255.248?
10.56.176.0 is your network. 255.255.240.0 is your subnet mask. Valid broadcast addresses would be 10.56.176.255 (network broadcast) and 255.255.255.255 (general network broadcast). The general network broadcast would actually broadcast to every machine on the internet, but internet routers will block all traffic from it to prevent this. In effect if you use either 10.56.176.255 or 255.255.255.255, the result is broadcasting to all machines on your network.
Which portion of the IP address 175.124.35.4 represents the host?
depends on the subnet mask ie/ 255.255.255.252 which would mean 175.124.35.0,4,8,12,16etc etc are networks and 175.124.35.1 & .2 are hosts. .3 is the broadcast address for that subnet.
Broadcast IP 123.123.2.5 and a subnet mask of 255.255.255.224?
First, convert the relevant portion of the subnet mask to binary: 255.255.255.1110 0000[1], aka /27. Next the last octet of the IP address (slightly more complex, but 5's an easy one): 0000 0101.That means the network is 123.123.2.0/27, the all-host-bits-1 broadcast address is at 123.123.2.31, and available host addresses are 30 hosts from 123.123.2.1 to 123.123.2.30 .[1] I skipped the all-ones octets, because they're not really necessary to write out.If you want it slightly more expanded:Subnet mask: 1111 1111.1111 1111.1111 1111.1111 1111.1110 0000IP address: 0111 1011.0111 1011.0000 0010.0000 0101Network address: 0111 1011.0111 1011.0000 0010.0000 0000For each bit of the subnet mask that is 1, you take the equivalent bit out of the IP address, and the rest you fill with 0. If you prefer that terminology, you perform a bitwise AND of subnet mask and IP address.Broadcast address: 0111 1011.0111 1011.0000 0010.0001 1111For the broadcast address, take the network address and fill the host bits with 1s instead of 0 (this is why they're also called all-0s and all-1s respectively).Now just convert that binary broadcast address back to decimal: 123.123.2.31(ProTip: You already know three of those octets because of where you got them from.)(ProTip: a nibble filled with 1s is 15 or 240 decimal, and a nibble filled with 0s is always 0)When you have the network address and the broadcast address, you also know the available host range for this subnet: one inward from each end, or 123.123.2.1 to 123.123.2.30 .
What is the host range for 192.168.1.0?
Assuming the subnet mask is 255.255.255.0 then... You range of total addresses is from 192.168.1.0 - 192.168.1.255 However, the first and last IP addresses cannot be assigned to hosts since they are reserved for internal usage. The first address, 192.168.1.0, is the subnet address. The last address, 192.168.1.255, is the broadcast address. Thus, the host range is from 192.168.1.1 - 192.168.1.254
What is the broadcast address on IPv4 networks?
The broadcast address on IPv4 networks is the subnet address, padded on the right with ones. For example, if the subnet address is 192.168.x.y, with a subnet mask of 255.255.0.0, then the broadcast address is 192.168.255.255.
What is the difference between a Network address and Broadcast address?
When you set up a sub network you decide upon the subnet mask and this determines the network address (all zeros in the subnet portion of the address) and the broadcast address (all ones in the subnet portion of the address). When you assign the host addresses in your subnet, then you use the addresses between the network address and the broadcast address.
What does address 192.1.6.255 signify?
In a 24 bit subnet (subnet mask = 255.255.255.0), the address 192.1.6.255 is the broadcast address for the subnet 192.1.6.0/24.
What is the broadcast address for the host IP of 172.16.66.021?
That depends on the subnet's subnet mask.
If 255.255.255.240 is subnet address what is major broadcast address?
.248
Why 255 is the start range of subnet mask?
becasue its used as the broadcast address
What are subnet broadcast addresses?
This could be a couple of things, but you are likely referring to TCP/IP protocol broadcasts. A broadcast address is when a data packet is sent to a special address to which all nodes on the network are supposed to accept and optionally respond to. While a broadcast address is defined for the entire network, this is not implemented in practice. For an IP subnet, the last address in the subnet's address space is the broadcast. For example, if my subnet is defined as 192.168.1.0/24 (very common for consumer network hardware including Wi-Fi), this defines the following: the network itself is identified as 192.168.1.0, the subnet mask is 255.255.255.0 (24 binary 1s in a row), the usable host addresses are 192.168.1.1 through 192.168.1.254, and the broadcast address is 192.168.1.255.
How do you get the Broadcast address of an IP address?
The address before the next valid network address will be the broadcast address For Example:192.168.1.64 the broadcast address is 192.168.1.127
What is the broadcast address for the ip subnet 8.5.8.232 mask 255.255.0.0?
192.168.100.63 255.255.255.224
Subnet calculation for ip address 172.16.2.130 and subnet mask 255.255.255.128?
network: 172.16.2.128 Broadcast: 172.16.2.255 usable host range: 172.16.2.129 thru .254
What is the effect of a router on delimiting broadcast traffic and conserving bandwidth?
Generally speaking, routers will unicast-forward incoming packets which have a network broadcast address as destination, unless they are directly connected to that network/subnet and therefore know that the destination address is a broadcast address
Which combination of network address and subnet mask allows 62 hosts to be connected in a single subnet?
Network address 10.1.1.0 Subnet mask 255.255.255.192255 - 62 = 193Because the value 255 is the broadcast address we get the number 192193 - 1 = 192the answer is 192Sorry for my poor English i mean my bad English.
