no
Not possible without breaking it.
The object will be falling at 49 m/s.This is solved by multiplying the force of gravity (9.8 m/s) by the time you're calculating (5s).
youtube com/watch?v=dQw4w9WgXcQ
InstructionTypeOpcodeSymbolicRepresentationDescriptionData transfer00001010000010010010000100000001000000100000001100000100LOAD MQLOAD MQ,M(X)STOR M(X)LOAD M(X)LOAD -M(X)LOAD |M(X)|LOAD -|M(X)|Transfer contents of register MQ to the accumulator ACTransfer contents of memory location X to MQTransfer contents of accumulator to memory location XTransfer M(X) to the accumulatorTransfer -M(X) to the accumulatorTransfer absolute value of M(X) to the accumulatorTransfer -|M(X)| to the accumulatorUnconditionalbranch0000110100001110JUMP M(X,0:19)JUMP M(X,20:39)Take next instruction from left half of M(X)Take next instruction from right half of M(X)Conditionalbranch0000111100010000JUMP+M(X,0:19)JUMP+M(X,20:39)If number in the accumulator is nonnegative, take next instruction from left half of M(X)If number in the accumulator is nonnegative , take next instruction from right half of M(X)Arithmetic0000010100000111000001100000100000001011000011000001010000010101ADD M(X)ADD |M(X)|SUB M(X)SUB |M(X)|MUL M(X)DIV M(X)LSHRSHAdd M(X) to AC; put the result in ACAdd |M(X)| to AC; put the result in ACSubtract M(X) from AC; put the result in ACSubtract |M(X)} from AC; put the remainder in ACMultiply M(X) by M(Q); put most significant bits of result in AC, put less significant bits in M(Q)Divide AC by M(X); put the quotient in MQ and the remainder in ACMultiply accumulator by 2 (i.e., shift left one bit position)Divide accumulator by 2 (i.e., shift right one bit position)Address modify0001001000010011STOR M(X,8:19)STOR M(X,28:39)Replace left address field at M(X) by 12 right-most bits of ACReplace right address field at M(X) by 12 right-most bits of AC
That is an expression and this way it can only be factored. m^2 - 49 (m - 7)(m + 7) Wanting an answer implies an equation. m^2 - 49 = 0 m^2 = 49 m = +/- 7 same answer
m * 49 = 7 Divide both sides by 49 to get m = 7 / 49 So and the fraction 7 / 49 can simplify to 1 / 7 So m = 1/7
Don't. This gun has parts held by pins. If you take it apart, you will end up at the gunsmith to put it back together- these are NOT meant to be taken down by the owner. Really.
4.4
18
Distribute the 49 and 81 first
There are approximately 14.9352 meters in 49 feet.
49,000
first you take the belt from around it take apart a few clamps and pull it striaght out.By the way ai,m only 12.
Ask a gunsmith for help if you don't have the factory supplied manual.
No.
Apart from 1, the only positive integer common factor of 49, 84, and 91 is 7.