dBm is defined as power ratio in decibel (dB) referenced to one milliwatt (mW). It is an
abbreviation for dB with respect to 1 mW and the "m" in dBm stands for milliwatt.
dBm is different from dB. dBm represents absolute power, whereas in audio engineering the
decibel is usually a voltage ratio of two values and is used then to represent gain or attenuation
of an audio amplifier, or an audio damping pad.
Well, the question your asking is basically impossible. It's like asking to convert a gallon of water into cans of pop. It is possible to convert the gallon of water into cans of water not soda. So you can convert dBm to watts, not dBi.
20 dbm
PdBm = 10*log10(1000*W)
dBw=dBm-30 then 75-30=45 dBw dBw=dBm-30 then 75-30=45 dBw dBw=dBm-30 then 75-30=45 dBw
dB or dBW relativ to 1W : dBm for dB relativ to 1 milliwatt. 0 dBm= 1 mW = -30dBW . Its interesting,but these terms are used interchangeably at times, erroneously.The term dBm is used by communications engineers and it is absolute.Most Power meters commercially available have this scale. It is : dBm=10log(base 10)(P1/P2) at two different Power points.Power is read always across a 50 Ohm resistor.IEEE has made this a standard and 1mW=0dBm(-40dBm is 100nW accross 50 Ohm and +20dBm is 100mW). As far as I know dB(not DB)refers simly to gain(and loss/attenuation as -dB).It is different this time as the equation is not Power but a simple ratio: dB=20log(base 10)(Gain or attenuation).One can have a reference and above that reference he is talking in positive dBs(Gain) and below in negative dBs(loss or attenuation).Such scales can then be modified as we have done for Acoustic Emission where we talk in dBae and our refence is the "perfect" sensor giving us ONLY 1microVolt(!) Peak output noise.Anyway a good goal.So for 40dBae a sensor/Amplifier(40dB Gain)output across a 50 Ohm resistor is 10mV.
Well, the question your asking is basically impossible. It's like asking to convert a gallon of water into cans of pop. It is possible to convert the gallon of water into cans of water not soda. So you can convert dBm to watts, not dBi.
Well, the question your asking is basically impossible. It's like asking to convert a gallon of water into cans of pop. It is possible to convert the gallon of water into cans of water not soda. So you can convert dBm to watts, not dBi.
20 dbm
Two ways to do it. In this particular problem, it's a matter of opinionwhich one is easier and which one is harder.Way #1:Convert dBm to watts, multiply by gains, convert output watts to dBm.+20 dBm = 0.1 watt.Output power = (0.1 watt) x (ap1) x (ap2) x (ap3) = 0.1 x 10 x 4 x 23 = 92 watts = +49.64 dBmWay #2:Convert each gain ratio to dB, then add all dB to input power.ap1 = 10 = 10 dBap2 = 4 = 6.02 dBap3 = 23 = 13.62 dB+20 dBm + 10dB + 6.02 dB + 13.62 dB = +49.64 dBm
the first convert the power in dBm to MW, the define of dBm=10 log (P MW) -10 log ( 1mw). example: let P=-2 dBm convert this to dB? answer: Pmw= inv log(-2/10)=0.630mw*1000 micw/mw=630 microw 10log(630)=28dB
PdBm = 10*log10(1000*W)
The 'm' in dBm means the power is referenced to 1mW. So, the power in dBm equals 10 times the log of the power in mW, or P(dBm) = 10*log(P(mW)/1mW). For example, 1W = 1000mW, so 10*log(1000/1) = 30dBm.
A decibel is a measure of relative power, to compare one power level with another. 'dBm' means dB relative to 1 milliwatt and is a common unit of power in communications systms, and 0 dBm is the same thing as 1 milliwatt.
The actual received power is in micro watts,its not possible to denote such values every time we need to use it so we convert it into dbm....by using logarithm...after conversion its negative... this is the same concept in gsm rx level
dBm is defined as power ratio in decibel (dB) referenced to one milliwatt (mW). It is an abbreviation for dB with respect to 1 mW and the "m" in dBm stands for milliwatt. dBm is different from dB. dBm represents absolute power, whereas in audio engineering the decibel is usually a voltage ratio of two values and is used then to represent gain or attenuation of an audio amplifier, or an audio damping pad.
Put the power in milliwatts in cell A2, and then use the following formula to get the power in dBm. =10 * LOG(A2)
It the unit is watts, megawatts is millions of watts, so to convert watts to megawatts, multiply the number of watts be 1,000,000.