The axial bond is 158 pm and the equatorial is 152 pm.
One explanation is that the hybridisation of the equatorial bonds is sp2 and the hybridisation of the equatorial is pd, the greater s character of the equatorial making the bond shorter. (taken from text book Inorganic chemistry by House)
I know of no theretical study that backs this up.
Most text books duck this ,e.g Greenwood and Wiberg.
The axial bonds in PF5 are longer than the equatorial bonds due to greater repulsion between the lone pair on the phosphorus atom and the axial fluorine atoms. The lone pair occupies more space around the phosphorus atom, causing the axial bonds to be stretched further away compared to the equatorial bonds. This results in a more stable geometry where the bond angles are closer to 90 degrees.
PCl3F2 has a trigonal bipyramidal molecular geometry, with three equatorial P-Cl bonds and two axial P-F bonds. The lone pair on phosphorus occupies one of the equatorial positions.
BCl3 has no pi bonds. It consists of three sigma bonds formed between boron and each chlorine atom, resulting in a trigonal planar molecular geometry.
The unequal bond lengths in PCl5 are due to the presence of lone pairs on the central phosphorus atom. The lone pairs repel the bonding pairs, causing distortion in the molecule's geometry. This leads to longer bonds for the axial P-Cl bonds compared to the equatorial P-Cl bonds.
The molecular geometry is tetrahedral when a central carbon atom bonds to four other atoms. This means the four atoms bonded to the central carbon atom are arranged in a way that resembles a pyramid with a triangular base.
Think of the sulfite ion as a molecule with its geometry and dipole moment AND a net charge. The electron pair geometry is tetrahedral and the molecular geometry is trigonal pyramidal and because of its asymmetrical shape and polar bonds, sulfite has a net dipole moment (2.04D ). The ion is polar.
axial bonds are longer than equatorial bonds becz axial bond contain very less "s" character as compare to equatorial bond, hence probability of finding it near nucleus is less hence force of attraction by nucleus is less as compare to to equatorial bonds
The geometry for a compound with dsp3 hybridization is called trigonal bipyramidal. It consists of five electron pairs arranged in a trigonal bipyramidal shape, with three equatorial bonds and two axial bonds.
PCl3F2 has a trigonal bipyramidal molecular geometry, with three equatorial P-Cl bonds and two axial P-F bonds. The lone pair on phosphorus occupies one of the equatorial positions.
All of the hydrogens on methane are evenly spaced apart at 109.5 degree bonds. This makes the geometry tetrahedral.
tetrahederal.
Since there is 4 electron domains which are all single bonds without any lone pairs, the molecular geometry is tetrahedral.
BCl3 has no pi bonds. It consists of three sigma bonds formed between boron and each chlorine atom, resulting in a trigonal planar molecular geometry.
In predicting molecular geometries, unshared electron pairs and double bonds influence the overall shape of a molecule. Unshared electron pairs tend to repel bonding pairs, causing distortions in the molecular geometry. Double bonds restrict rotation around the bond axis, affecting the spatial arrangement of the surrounding atoms and leading to a fixed geometry for the molecule.
I would imagine it has a tetrahedral geometry since the Cl atoms are quite large in size, thus electron replusion is high, so adopts a geometry that gives the largest angle between the C-Cl bonds.
Trigonal Pyramidal
The molecular geometry of CS2 is linear. This molecule consists of a central carbon atom bonded to two sulfur atoms, and there are no lone pairs on the central atom. The bonds and atoms are arranged in a straight line, giving it a linear molecular geometry.
Methane has tetrahedral geometry. In methane carbon undergoes sp3 hybridisation. The four sp3 hybrid orbitals form four sigma bonds with four 1s orbitals of hydrogen atoms.