To find the number of moles of chloroform in 215 g, you need to divide the given mass by the molar mass of chloroform. The molar mass of chloroform (CHCl3) is approximately 119.38 g/mol. Therefore, 215 g of chloroform is equal to 1.80 moles.
The density of chloroform is 1.489 grams per milliliter. To find the volume of 101.5 grams of chloroform, divide the mass by the density: 101.5 grams / 1.489 grams per milliliter = 68.07 milliliters.
Chloroform is a colorless liquid with a sweet odor used as a solvent, while chloroform water is a solution in which chloroform is mixed with water. Chloroform water is a mixture of chloroform and water, typically used in laboratory settings for certain chemical reactions.
To calculate the percent composition by mass of chloroform (CHCl3), find the molar mass of each element (carbon, hydrogen, and chlorine) and the total molar mass of chloroform. Then, divide the molar mass of each element by the total molar mass and multiply by 100 to get the percentage of each element in chloroform.
To find the number of moles in 59.1 g of chloroform (CHCl3), you need to divide the given mass by the molar mass of chloroform. The molar mass of chloroform is approximately 119.38 g/mol. Dividing 59.1 g by 119.38 g/mol gives approximately 0.495 moles of chloroform.
Chloroform is not a cell. it is a organic compound.
To find the number of moles of chloroform in 215 g, you need to divide the given mass by the molar mass of chloroform. The molar mass of chloroform (CHCl3) is approximately 119.38 g/mol. Therefore, 215 g of chloroform is equal to 1.80 moles.
The density of chloroform is 1.489 grams per milliliter. To find the volume of 101.5 grams of chloroform, divide the mass by the density: 101.5 grams / 1.489 grams per milliliter = 68.07 milliliters.
Chloroform is a colorless liquid with a sweet odor used as a solvent, while chloroform water is a solution in which chloroform is mixed with water. Chloroform water is a mixture of chloroform and water, typically used in laboratory settings for certain chemical reactions.
To calculate the percent composition by mass of chloroform (CHCl3), find the molar mass of each element (carbon, hydrogen, and chlorine) and the total molar mass of chloroform. Then, divide the molar mass of each element by the total molar mass and multiply by 100 to get the percentage of each element in chloroform.
To find the number of moles in 59.1 g of chloroform (CHCl3), you need to divide the given mass by the molar mass of chloroform. The molar mass of chloroform is approximately 119.38 g/mol. Dividing 59.1 g by 119.38 g/mol gives approximately 0.495 moles of chloroform.
Chloroform.
Normally they arew not for sale. But you can find it in laboratories.
Sodium chloride doesn't react with chloroform and is not soluble in chloroform.
Chloroform spirit, also known as chloroform water or chloroform solution, typically consists of chloroform mixed with water and ethanol. The exact composition may vary depending on the specific formulation.
The solubility of benzoic acid in chloroform is approximately 3.5 g/L at room temperature.
Yes, iodine is soluble in chloroform. Chloroform is a nonpolar solvent, and iodine is slightly soluble in nonpolar solvents like chloroform.