The freezing point depression constant for water is 1.86°C kg/mol. First, calculate the molality of the solution: 3 mol NaCl / 1 kg H2O = 3 mol/kg. Next, calculate the freezing point depression: ΔTf = iKfm where i is the van't Hoff factor (2 for NaCl), Kf is the freezing point depression constant, and m is the molality. Plugging in the values, the final freezing point would be -11.16°C.
The freezing point depression can be calculated using the formula ΔTf = Kf * m, where Kf is the freezing point depression constant (1.86 °C/kg) and m is the molality of the solution. With 3 mol of sugar dissolved in 1 kg of water, the molality is 3 mol / 1 kg = 3 mol/kg. Thus, the freezing point depression would be ΔTf = 1.86 °C/kg * 3 mol/kg = 5.58 °C. The final freezing point of the solution would be the freezing point of water (0°C) minus the freezing point depression, so the final freezing point would be -5.58°C.
The freezing point depression constant for water is -1.86°C/m. Using the formula ΔTf = i * Kf * m, where i is the van't Hoff factor (for sugar = 1 since it doesn't dissociate), Kf is the freezing point depression constant, and m is the molality, we can calculate the change in freezing point. 3 moles of sugar in 1 kg of water is roughly a 0.111 molal solution. Therefore, the final freezing point of the solution would be around -0.206°C.
The freezing point of water would decrease if 4 mol of NaCl were added because NaCl is a solute that disrupts the water molecules' ability to form solid ice. Each mole of NaCl added to water reduces the freezing point by approximately 1.86 degrees Celsius. So, with 4 mol of NaCl added, the freezing point of water would decrease by about 7.44 degrees Celsius.
When salt is added to water, the freezing point of the water decreases. This is due to the salt disrupting the formation of ice crystals in the water, requiring a lower temperature for the water to freeze.
The freezing point of water decreases by about 1.86 degrees Celsius for each mole of solute (such as sugar) dissolved in 1 kg of water. So, the freezing point would decrease by 1.86 degrees Celsius for every mole of sugar added.
-5.58 C
-5.58 C
The freezing point depression can be calculated using the formula ΔTf = Kf * m, where Kf is the freezing point depression constant (1.86 °C/kg) and m is the molality of the solution. With 3 mol of sugar dissolved in 1 kg of water, the molality is 3 mol / 1 kg = 3 mol/kg. Thus, the freezing point depression would be ΔTf = 1.86 °C/kg * 3 mol/kg = 5.58 °C. The final freezing point of the solution would be the freezing point of water (0°C) minus the freezing point depression, so the final freezing point would be -5.58°C.
The freezing point depression constant for water is -1.86°C/m. Using the formula ΔTf = i * Kf * m, where i is the van't Hoff factor (for sugar = 1 since it doesn't dissociate), Kf is the freezing point depression constant, and m is the molality, we can calculate the change in freezing point. 3 moles of sugar in 1 kg of water is roughly a 0.111 molal solution. Therefore, the final freezing point of the solution would be around -0.206°C.
The freezing point of water would decrease if 4 mol of NaCl were added because NaCl is a solute that disrupts the water molecules' ability to form solid ice. Each mole of NaCl added to water reduces the freezing point by approximately 1.86 degrees Celsius. So, with 4 mol of NaCl added, the freezing point of water would decrease by about 7.44 degrees Celsius.
It drops to about 12 degrees Fahrenheit.
When salt is added to water, the freezing point of the water decreases. This is due to the salt disrupting the formation of ice crystals in the water, requiring a lower temperature for the water to freeze.
The freezing point decrease is -14,8 oC.
The normal freezing temperature for pure water is 0c. Howeverif sugar is added in the pure water, the freezing point will be lower than zero. How far below zero will depend on the sugar concentration in the water.
The freezing point of water decreases by about 1.86 degrees Celsius for each mole of solute (such as sugar) dissolved in 1 kg of water. So, the freezing point would decrease by 1.86 degrees Celsius for every mole of sugar added.
The normal freezing temperature for pure water is 0c. Howeverif sugar is added in the pure water, the freezing point will be lower than zero. How far below zero will depend on the sugar concentration in the water.
When antifreeze is added to water, it lowers the freezing point and raises the boiling point of the mixture. This helps prevent the water from freezing in cold temperatures and boiling in hot temperatures, making it more suitable for use as engine coolant.