consider the balance chemical equation, suppose the reaction with oxalic acid 2MnO4- + 16H+ + 5C2O4 --> 2Mn+2 + 8H2O + 10CO2 Above reaction shows that the reaction requires a number of protons to occur, H2SO4 is the source of these protons.
The reaction between Cu3(PO4)2 and KMnO4 would likely result in the formation of CuSO4, MnO2, and K3PO4 as the products. The manganese in KMnO4 would be reduced from +7 to +4 oxidation state, leading to the formation of MnO2. The copper ions from Cu3(PO4)2 would likely form copper(II) sulfate (CuSO4), while potassium phosphate (K3PO4) would also be formed.
Glacial acetic acid is a concentrated form of acetic acid, which is a reducing agent. When mixed with potassium permanganate (KMnO4), which is an oxidizing agent, a vigorous reaction can occur, resulting in the release of heat, gas, and potentially causing a fire or explosion. This reaction is dangerous and should be avoided.
H2SO4 is typically used instead of HCl in the titration of KMnO4 because HCl can react with KMnO4 and form chlorine gas, which can interfere with the titration results. Additionally, H2SO4 provides the required acidic medium for the reaction to occur between KMnO4 and the analyte.
The reaction between an aldehyde and acidified potassium permanganate (KMnO4) typically results in oxidation of the aldehyde to a carboxylic acid. The general equation for this reaction is RCHO + KMnO4 + H+ → RCOOH + MnO2 + K+.
This reaction is the following:2 KMnO4 + SO2 = 2 MnO2 + K2SO4
consider the balance chemical equation, suppose the reaction with oxalic acid 2MnO4- + 16H+ + 5C2O4 --> 2Mn+2 + 8H2O + 10CO2 Above reaction shows that the reaction requires a number of protons to occur, H2SO4 is the source of these protons.
The reaction between Cu3(PO4)2 and KMnO4 would likely result in the formation of CuSO4, MnO2, and K3PO4 as the products. The manganese in KMnO4 would be reduced from +7 to +4 oxidation state, leading to the formation of MnO2. The copper ions from Cu3(PO4)2 would likely form copper(II) sulfate (CuSO4), while potassium phosphate (K3PO4) would also be formed.
Glacial acetic acid is a concentrated form of acetic acid, which is a reducing agent. When mixed with potassium permanganate (KMnO4), which is an oxidizing agent, a vigorous reaction can occur, resulting in the release of heat, gas, and potentially causing a fire or explosion. This reaction is dangerous and should be avoided.
no reaction equation
H2SO4 is typically used instead of HCl in the titration of KMnO4 because HCl can react with KMnO4 and form chlorine gas, which can interfere with the titration results. Additionally, H2SO4 provides the required acidic medium for the reaction to occur between KMnO4 and the analyte.
The reaction between an aldehyde and acidified potassium permanganate (KMnO4) typically results in oxidation of the aldehyde to a carboxylic acid. The general equation for this reaction is RCHO + KMnO4 + H+ → RCOOH + MnO2 + K+.
HCl cannot be used to acidify KMnO4 solution in permanganometric titration because it will react with KMnO4 reducing it to MnO2, which interferes with the titration process and affects the accuracy of the results. Instead, dilute sulfuric acid (H2SO4) is typically used to acidify the KMnO4 solution, as it does not interfere with the redox reaction between KMnO4 and the analyte.
When ethanol reacts with excess acidified KMnO4, it is oxidized to form ethanoic acid. The purple color of KMnO4 is decolorized to colorless Mn2+ ions during the reaction.
In this reaction, potassium permanganate (KMnO4) acts as the oxidizing agent. It oxidizes oxalic acid (H2C2O4) to carbon dioxide and sulfuric acid (H2SO4) helps to provide the acidic conditions needed for the reaction to occur.
When KMnO4 is added to ethanol, it gets reduced to MnO2, causing the initial color change. However, when excess KMnO4 is added, MnO2 gets further oxidized back to KMnO4, resulting in the reappearance of the original color. This demonstrates the redox nature of the reaction between KMnO4 and ethanol.
When potassium permanganate (KMnO4) reacts with formaldehyde (HCHO), it undergoes oxidation-reduction reaction. The purple color of KMnO4 fades as it gets reduced to Mn2+ ions, while formaldehyde is oxidized to formic acid (HCOOH) or carbon dioxide and water. Heat may be evolved during the reaction.