Using the given balanced chemical equation, you can see that for every 1 mole of N2, 3 moles of H2 are needed to produce 2 moles of NH3. Therefore, you need 3/1 = 3 moles of H2 for 1 mole of N2. Since you have 14.5 moles of N2, you would need 14.5 moles x 3 moles = 43.5 moles of H2.
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
1/2 n2 + 3/2 h2 = nh3 sorry about the lower case they wouldn't let me summit it with caps N2 + 3 H2 => 2 NH3
To determine the grams of nitrogen needed, calculate the molar mass of ammonia (NH3) which is 17 grams/mole. Then, use the mole ratio from the balanced equation (1 mol N2:2 mol NH3) to find the mass of nitrogen required which is 16.5 grams.
The reaction of 2 liters of N2 and 2 liters of H2 to form NH3 is based on the balanced equation: N2 + 3H2 -> 2NH3. Since 1 mole of N2 reacts with 3 moles of H2 to form 2 moles of NH3, 2 liters of N2 and 2 liters of H2 would produce 2 liters of NH3 following the stoichiometry of the balanced equation.
(N2) + 3(H2) = 2(NH3)
This is a synthesis reaction.
16,45 g nitrogen are needed.
The balanced equation for the reaction of hydrogen gas (H2) with nitrogen gas (N2) to form ammonia (NH3) is: 3H2 + N2 → 2NH3
The formula for the synthesis of ammonia from diatomic nitrogen and hydrogen is: N2+3H2-->2NH3
True, the balanced equation N2 + 3H2 -> 2NH3 shows that 1 mole of N2 reacts with 3 moles of H2 to form 2 moles of NH3. From the molar masses of N2 (28g/mol), H2 (2g/mol), and NH3 (17g/mol), it can be calculated that 1g of N2 reacts with 3g of H2 to form 2g of NH3.
No, it's not balanced because the number of hydrogens and nitrogens on the left is not equal to the number on the right. 3H2 + N2 --> 2NH3
Put a 2 to NH3 first.Then a 3 to Hydrogen.
Three: The reaction equation is N2 + 3 H2 -> 2 NH3
Using the given balanced chemical equation, you can see that for every 1 mole of N2, 3 moles of H2 are needed to produce 2 moles of NH3. Therefore, you need 3/1 = 3 moles of H2 for 1 mole of N2. Since you have 14.5 moles of N2, you would need 14.5 moles x 3 moles = 43.5 moles of H2.
keq = 1.125
In the reaction N2 + 3H2 → 2NH3, nitrogen (N2) is reduced because it gains hydrogen atoms, and hydrogen (H2) is oxidized because it loses electrons.