The balanced equation for the reaction would be: 2ClO + 2HCl + C6H10O5 + 2KI → 2KCl + 2H2O + CO2 + I2.
2 KBr + BaI2 ----> 2 KI + BaBr2
The balanced reaction is: 2Cl + 2KI → 2KCl + I2. It is balanced by ensuring there are the same number of each type of atom on both sides of the reaction arrow.
This is a double displacement reaction, also known as a metathesis reaction. In this reaction, the chlorine atoms in Cl2 and the iodide ions in KI swap partners to form potassium chloride (KCl) and iodine (I2).
The balanced equation is: Br2 + 2Kl -> 2KBr + I2. This means there is a 2 in front of the underlined substance, KI.
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
The reaction between potassium iodide and bromine forms potassium bromide and iodine. It is a redox reaction, where bromine gets reduced from 0 to -1 and iodide gets oxidized from -1 to 0. The reaction is represented by the following equation: 2KI + Br2 -> 2KBr + I2.
Cl2 + 2KI → 2KCl + I2
The balanced equation for the reaction would be: 2ClO + 2HCl + C6H10O5 + 2KI → 2KCl + 2H2O + CO2 + I2.
2 KBr + BaI2 ----> 2 KI + BaBr2
The reaction between potassium iodide and bromine produces potassium bromide and iodine. This is a redox reaction where bromine gets reduced to bromide ions, while iodide ions get oxidized to form elemental iodine. The balanced chemical equation for this reaction is 2 KI + Br2 → 2 KBr + I2.
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
The balanced reaction is: 2Cl + 2KI → 2KCl + I2. It is balanced by ensuring there are the same number of each type of atom on both sides of the reaction arrow.
This is a double displacement reaction, also known as a metathesis reaction. In this reaction, the chlorine atoms in Cl2 and the iodide ions in KI swap partners to form potassium chloride (KCl) and iodine (I2).
The balanced equation is: Br2 + 2Kl -> 2KBr + I2. This means there is a 2 in front of the underlined substance, KI.
This is a double replacement reaction which forms barium sulfate and salt (NaCl) when the sodium ions in sodium sulfate (mirabilite) remove chlorine from barium chloride.
The equation for the reaction of potassium bromide with aqueous iodine is: 2KBr (aq) + I2 (aq) → 2KI (aq) + Br2 (aq) This reaction demonstrates a redox reaction where bromide ions are oxidized to bromine, and iodine is reduced to iodide.